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xxMikexx [17]
2 years ago
12

If the area of one face of a cube is 64cm^2, what is the cube's surface area? Please enter your answer in numbers only, don't en

ter the units.
Mathematics
2 answers:
Dafna1 [17]2 years ago
6 0
Since the area of one side of a cube is 64, you can find the surface area by adding the rest of the 5 sides which is:
64+64+64+64+64+64=384
Alecsey [184]2 years ago
4 0

Answer:

4096

Step-by-step explanation:

i think that is the answer because are you have to multiple them

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Answer:

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f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

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So f(0,0)=ln19.

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