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gtnhenbr [62]
3 years ago
7

12=y-3y what's the answer

Mathematics
2 answers:
nevsk [136]3 years ago
8 0
12=y-3y  Combine like terms
12=-2y  Divide
y=-6
Vitek1552 [10]3 years ago
7 0
<span>12=y-3y

the same    y - 3y = 12 

-2y = 12   divide by 2 both sides (2 is a common factor for 2 and 12)

- y = 6 (multiply with -1)

y = - 6

 </span>
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the isoceles triangle has a base that measures 14 units.the value of y, the length of each leg, must be
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Answer:

greater than 7

Step-by-step explanation:

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Find the ratio of the perimeter of the first figure to the perimeter of the second.
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Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student
AysviL [449]

Answer:

The mean calculated for this case is \bar X=584

And the 95% confidence interval is given by:

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=584

The sample deviation calculated s=86.776

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

3 0
3 years ago
Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the
stira [4]

Given:

The arithmetic sequence is −15, −33, −51, −69.

To find:

The nth term of the arithmetic sequence.

Solution:

We have,

−15, −33, −51, −69

Here,

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d = -33+15

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Now, nth term  of an arithmetic sequence is

a_n=a+(n-1)d

Substitute a=-15 and d=-18.

a_n=-15+(n-1)(-18)

a_n=-15-18n+18

a_n=-18n+3

Therefore, the nth term of the given arithmetic sequence is a_n=-18n+3.

4 0
3 years ago
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