Answer:
Step-by-step explanation:
Animal Person
y = 5.4x + 34 y = 12x + 8.5; where y - weight, x - years
looking for when weight (y) is the same, so we need
animal weight (y) = person weight (y)
5.4x + 34 = 12x + 8.5
<u> -5.4x -5.4x</u>
34 = 6.6x + 8.5
<u> -8.5 -8.5</u>
25.5 = 6.6x divide both sides by 6.6
x = 3.86 years
not sure if you need your answer in decimal or what, but you can adjust accordingly.
Answer:
12 days
Step-by-step explanation:
Answer:20.1 will be the temp
Step-by-step explanation:
All you do is add -3.9 and 24 together to get your answer
Answer:
A) 1
B) 1
C) 0
Step-by-step explanation:
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes
We solve this question using the z score formula
z = (x-μ)/σ/√n, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
n = number of random samples
A) Less than 10 minutes
x < 10
z = 10 - 8.2/ 1.5 / √49
z = 8.4
P-value from Z-Table:
P(x<10) = 1
B) Between 5 and 10 minutes
For x = 5 minutes
z = 5 - 8.2/ 1.5 / √49
z = -14.93333
P-value from Z-Table:
P(x = 5) = 0
For x = 10 minutes
z = 10 - 8.2/ 1.5 / √49
z = 8.4
P-value from Z-Table:
P(x = 10) = 1
The probability that the average time waiting in line for these customers is between 5 and 10 minutes
P(x = 10) - P(x = 5)
= 1 - 0
= 1
C) Less than 6 minutes
x < 6
z = 6 - 8.2/ 1.5 / √49
z = -10.26667
P-value from Z-Table:
P(x<6) = 0
Answer:
4762 N/m^2
Step-by-step explanation:
Find area.
30x5.6=168
Convert to m^2
168cm^2=0.0168m^2
Use pressure formula to get answer
P=F/A
P=80/0.0168
P=4762 N/m^2
