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Deffense [45]
3 years ago
7

5x + 2y = -10 3x + y = 66 please show work

Mathematics
2 answers:
liq [111]3 years ago
8 0

Answer:

x=142, y=-360. (142, -360).

Step-by-step explanation:

5x+2y=-10

3x+y=66

----------------

5x+2y=-10

-2(3x+y)=-2*66

-----------------------

5x+2y=-10

-6x-2y=-132

-------------------

-x=-142

x=142

3(142)+y=66

426+y=66

y=66-426

y=-360

Sauron [17]3 years ago
3 0

Answer:

1- 5x+2y+−2y=−10+−2y

5x=−2y−10

\frac{5}{5}= \frac{-2y-10}{5}

x= \frac{-2}{5}y-2

2-  3x+y+−y=66+−y

3x=−y+66

\frac{3x}{3} = \frac{-y+66}{3}

x=\frac{-1}{3}y+22

Step-by-step explanation:

This is the answers :)

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Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

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2A/12 < 2A/14 + 2A/h

Solve it and get

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2A/14 < 2A/12 + 2A/h

Solve it and get

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2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

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