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3 years ago

5x + 2y = -10 3x + y = 66 please show work

Mathematics

2 answers:

liq [111]3 years ago

8 0

Answer:

x=142, y=-360. (142, -360).

Step-by-step explanation:

5x+2y=-10

3x+y=66

----------------

5x+2y=-10

-2(3x+y)=-2*66

-----------------------

5x+2y=-10

-6x-2y=-132

-------------------

-x=-142

x=142

3(142)+y=66

426+y=66

y=66-426

y=-360

Sauron [17]3 years ago

3 0

Answer:

1- 5x+2y+−2y=−10+−2y

5x=−2y−10

$\frac{5}{5}$ = $\frac{-2y-10}{5}$

x= $\frac{-2}{5}y-2$

2- 3x+y+−y=66+−y

3x=−y+66

$\frac{3x}{3} = \frac{-y+66}{3}$

$x=\frac{-1}{3}y+22$

Step-by-step explanation:

This is the answers :)

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A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes

Rudik [331]

A triangle is an example of a class of figures referred to as plane shapes. It has three straight sides and three internal angles which sum up to $180^{o}$ . The measures of the internal angles of the triangle given in the question are A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

Considering the given question, let the sides of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the Cosine rule to have:

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos C

So that;

$7^{2}$ = $6^{2}$ + $(6.5)^{2}$ - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

= 29.25

Cos C = $\frac{29.25}{78}$

= 0.375

C = $Cos^{-1}$ 0.375

= 67.9757

C = $68^{o}$

Apply the Sine rule to determine the value of B,

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{6.5}{Sin B}$ = $\frac{7}{Sin 68}$

SIn B = $\frac{6.5 *Sin 68}{7}$

= 0.861

B = $Sin^{-1}$ 0.861

= 59.43

B = $59.4^{o}$

Thus to determine the value of A, we have;

A + B + C = $180^{o}$

A + $59.4^{o}$ + $68^{o}$ = $180^{o}$

A = $180^{o}$ - 127.4

= 52.6

A = $52.6^{o}$

Therefore the sizes of the internal angles of the triangle are: A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

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2 years ago

When Carson runs the 400 meter dash, his finishing times are normally distributed with a mean of 65 seconds and a standard devia

just olya [345]

Given Information:

Mean time to finish 400 meter dash = μ = 65 seconds

Standard deviation to finish 400 meter dash = σ = 2.5 seconds

Confidence level = 95%

Required Information:

95% confidence interval = ?

Answer:

$CI = 60 \: to \: 70 \: seconds$

Step-by-step explanation:

In the normal distribution, the empirical rule states approximately 68% of all the data lie within 1 standard deviation from the mean, approximately 95% of all the data lie within 2 standard deviations from the mean and approximately 99.7% of all the data lie within 3 standard deviations from the mean.

The confidence interval for 95% confidence limit is given by

$CI = \mu \pm 2\sigma$

Since approximately 95% of all the data lie within 2 standard deviations from the mean. μ is the mean time Carson takes to finish 400 meter dash and σ is the standard deviation.

$CI = 65 \pm 2(2.5)$