Answer:
The new coordinate of B' will be ( -1, 6)
Answer:
Quadrant III
Step-by-step explanation:
The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.
The graphs shown are of the functions:




<em>So, any linear function of the form
with
and
does not pass through Quadrant III. Answer choice 3 is correct.</em>
It hits the ground at h=0
0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t
t+3=0
t=-3, nope, we can't have negative time
at t=2, or 2 seconds