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3 years ago

Who can tell me what all the prime numbers are,please!!!!!!!!!!!!!

Mathematics

2 answers:

Oxana [17]3 years ago

8 0

There are an infinite amount of prime numbers plz be more clear on the range

Volgvan3 years ago

6 0

Prime numbers are numbers that only have one pair of multiples; 1 and the number itself. I can't give you all the possible prime numbers, but I'll at least give you the prime numbers between 1 and 100.

1
2
3
5
7
11
13
17
19
23
29
31
37
41
43
47
53
59
61
67
71
73
79
83
89
97

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Answer is C.
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A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

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3 years ago

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kirill115 [55]

Answer:

I think the answer is -140

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2 years ago

Please help me with this one! Its due today. Thank you ^^

larisa [96]

Step-by-step explanation:

the sum of all angles around a single point on one side of a line is always 180° (a line can always be seen as the diameter of an imaginary circle, so each side corresponds to 180°).

the angles on one side of a line crossed by a second line are mirrored but otherwise exactly the same as on the other side of the line.

a parallel line crossing a third line must have the exact same angles with this third line as the other parallel line. otherwise they would not be parallel. you can say a parallel line mimics the exact same behavior as the other line it is parallel to.

so,

c = 180 - 35 = 145°

a = c = 145°

b = 35°

d = 180 - 110 = 70°

e = d = 70°

f = 110°

g = 180 - 125 = 55°

i = g = 55°

h = 125°

j = 180 - 130 = 50°

m = j = 50°

o = k = d = e = 70° (as this line crosses 2 levels)

l = f = 110°

n = 180 - m - o = 180 - 50 - 70 = 60°

s = 180 - 23 = 157°

p = 23°

r = 68°

q = 180 - p - r = 180 - 23 - 68 = 89°

t = 180 - 68 = 112°

v = w = z = 132° (as this line crosses 2 levels)

A = 180 - 132 = 48°

y = x = u = A = 48°

B = 180 - 39 - 47 = 94°

D = B = 94°

C = 39 + 47 = 86°

E = 47°

F = B + 39 = 94 + 39 = 133°

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2 years ago