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KonstantinChe [14]
3 years ago
12

I need help with my math! The problem is : 150% of what number is 18

Mathematics
1 answer:
Andreas93 [3]3 years ago
7 0
The answer would be 27 =)
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Which of the following is equivalent to4−(−5∗9−1)÷2+(5)2−7?
Gala2k [10]

Answer:

-20

Step-by-step explanation:

Follow the PEDMAS order (from top to bottom):

Parentheses

Exponents

Division and Multiplication

Addition and Subtraction

(-5 × 9 - 1) ÷ 2 + (5)2 - 7

(-45 - 1) ÷ 2 + 10 - 7

-46 ÷ 2 + 10 - 7

-23 + 10 - 7

-13 - 7

-20

8 0
3 years ago
Read 2 more answers
The functions f(x) = −(x − 1)2 + 5 and g(x) = (x + 2)2 − 3 have been rewritten using the completing-the-square method. Apply you
Pepsi [2]

Answer:

The vertex form of a quadratic function:

(h,k) - the coordinates of the vertex

If a>0, then the parabola opens upwards, so the vertex is the minimum of the function.

If a<0, then the parabola opens downwards, so the vertex is the maximum of the function.

7 0
3 years ago
Differentiating Exponential Functions In Exercise, find the derivative of the function.<br> y = x2ex
I am Lyosha [343]

Answer:

y' = xe^{x}(2 + x)

Step-by-step explanation:

If we have a product function y, in the following format

y = f(x)*g(x)

This function has the following derivative

y' = f'(x)*g(x) + g'(x)*f(x)

In this problem, we have that:

y = x^{2}e^{x}

So

f(x) = x^{2}, f'(x) = 2x, g(x) = e^{x}, g'(x) = e^{x}

The derivative of the function is:

y' = f'(x)*g(x) + g'(x)*f(x)

y' = 2xe^{x} + x^{2}e^{x}

y' = e^{x}(2x + x^{2})

y' = xe^{x}(2 + x)

8 0
3 years ago
Given the rule: y is 5 more than x, when x=5 what is the value of y?
max2010maxim [7]
The value of y should be 8
4 0
3 years ago
Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

7 0
3 years ago
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