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kodGreya [7K]
3 years ago
11

2. Suppose the temperature that most foods can stay bacteria free in restaurants varies approximately according to a normal dist

ribution with a mean of 31.3 degrees and a standard deviation of 2.8 degrees Fahrenheit. The Federal Department of Agriculture mandates that food inspectors make sure that all restaurants fine a location up to $1,500.00 if the temperature in cold food storage goes above the bottom 15% of that distribution for safety and insurance purposes. What temperature correlates to the bottom 15% of this distribution?
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

28.4

Step-by-step explanation:

Given that:

Mean, m = 31.3

Standard deviation, s = 2.8

Since, data is normally distributed :

P(x < 0.15) gives a Z value of - 1.036

Using the Zscore formula :

Z = (x - mean) / standard deviation

-1.036 = (x - 31.3) / 2.8

-1.036 * 2.8 = x - 31.3

-2.9008 = x - 31.3

-2.9008 + 31.3 = x

28.3992 = x

The temperature which correlates to the bottom 15% of the distribution is 28.4

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Answer:

110°

Step-by-step explanation:

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3 years ago
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Answer:

<em>8 C sometimes</em>

<em>9 64x^8 y^11</em>

<em>10 c 1.28r^2/ t^9</em>

Step-by-step explanation:

<u>Algebraic Operations </u>

Some basic rules must be fresh in our minds when trying to simplify complex algebraic expressions. For example, the power rule respect to the product or quotient:

\displaystyle \left(\frac{x^n.y^m}{z^p}\right)^q= \frac{x^{qn}.y^{qm}}{z^{qp}}

\displaystyle \frac{x^n.x^q}{x^p}= x^{n+q-p}

\displaystyle x^{-n}=\frac{1}{x^n}

Let's face the questions at hand

8. A number is raised to a negative exponent is negative?

Following the expressions recalled above, let's pick the expression

\displaystyle 3^{-2}=\frac{1}{3^2}=\frac{1}{9}

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\displaystyle (-2)^{-3}=\frac{1}{(-2)^3}=-\frac{1}{8}

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<em>Answer: C sometimes </em>

9 simplify(4xy^2)^3(xy)^5

(4xy^2)^3(xy)^5=4^3x^3(y^2)^3x^5y^5

=64x^3y^6x^5y^5

=64x^8y^{11}

10 simplify(2t^-3)^3(0.4r)^2

(2t^{-3})^3(0.4r)^2=2^3(t^{-3})^30.4^2r^2

=8t^{-9} 0.16 r^2

=1.28t^{-9} r^2

\displaystyle \frac{1.28 r^2}{t^9}

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the sides of a rectangle are in the ratio 2:5. if the longer side of the rectangle is 25.5 in., what are it's width, perimeter,
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25.5/5=5.1

5.1*2=10.2

The width is 10.2 inches

25.5*2+10.2*2=71.4

The perimeter is 71.4 inches

20.5*10.2=260.1

The area is 260.1

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