Answer:
The answer to your question is below
Explanation:
1. iron + copper(II) sulfate ⇒ Iron sulfate + copper
Fe + CuSO₄ ⇒ FeSO₄ + Cu
This is a single replacement reaction
2. potassium chloride + mercury(I) sulfate ⇒ potassium sulfate + mercury (I) chloride
2KCl + Hg₂SO₄ ⇒ K₂SO₄ + 2HgCl
This is a double replacement reaction
3. Sulfur + oxygen ⇒ sulfur dioxide
S + O₂ ⇒ SO₂
This is a synthesis reaction
Now, all the reactions are balanced.
Molar mass :
Li₂S = <span>45.947 g/mol
AlCl</span>₃ = <span>133.34 g/mol
</span><span>3 Li</span>₂<span>S + 2 AlCl</span>₃<span> = 6 LiCl + Al</span>₂S₃
3 * 45.947 g Li₂S ----------> 2 * <span>133.34 g AlCl</span>₃
1.084 g Li₂S ----------------> ?
Mass Li₂S = 1.084 * 2 * 133.34 / 3 * 45.947
Mass Li₂S = 289.08112 / 137.841
Mass Li₂S = 2.0972 g
hope this helps!
The volume of carbon dioxide that will be produced is 191.4 g.
Calculation:
The following is the balanced equation for the given reaction:
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g),
It is obvious that when 1.0 mole of Fe2O3 reacts with 3.0 mole of CO, 2.0 mole of Fe and 3.0 mole of CO2 are produced.
Hence by using cross multiplication:
If 2.0 mol of Fe was produced with → 3.0 mol of CO₂, from stoichiometry.
Then how many moles of CO₂ are produced by 2.9 mol of Fe?
To find the answer we have a formula:
∴ The no. of moles of CO₂ produced = (3.0 mol)(2.9 mol)/(2.0 mol) = 4.35 mol.
∴ The mass of CO₂ produced = no. of moles x molar mass = (4.35 mol)(44.0 g/mol) = 191.4 g.
Learn more about the balanced reaction here:
brainly.com/question/15355912
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