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Elena L [17]
1 year ago
11

Cobalt-59 is the only stable isotope of this transition metal. One ⁵⁹Co atom has a mass of 58.933198 amu. Calculate the binding

energy(a) per nucleon in MeV;
Chemistry
1 answer:
Temka [501]1 year ago
5 0

Cobalt-59 is the only stable isotope of this transition metal. • Mass of proton = 1.00783 amu1.00783 amu

<h3>What is isotope ?</h3>

Isotopes are two or more atom types that share the same atomic number (number of protons in their nuclei), location in the periodic table, and chemical element but have distinct nucleon numbers (mass numbers) as a result of having a different number of neutrons in their nuclei. Although the chemical properties of each isotope of a given element are nearly identical, they differ in their atomic weights and physical characteristics.

The name "isotope" refers to the fact that different isotopes of a single element occupy the same location on the periodic table. The term "isotope" is derived from the Greek words isos ("equal") and topos ("place"), which together indicate "the same place." In 1913, Scottish physician and author Margaret Todd suggested the term to British chemist Frederick Soddy.

To learn more about isotope  from the given link:

brainly.com/question/364529

#SPJ4

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*<br> What is the volume, in liters, of 12.0 kg of H2 at STP?
neonofarm [45]

Answer:

According to Avogadro's law, the volume of one mole of any gas at Standard Temperature and Pressure (STP = 273 K and 1 atm) is 22.4 L. Two important Gas Laws are required in order to convert the experimentally determined volume of hydrogen gas to that at STP. 1.

Explanation:

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6 0
3 years ago
what is the proper scientific notation for 0.000476? a.0.476 × 10-3 b.4.76 × 10-4 c.47.6 × 10-5 d.476 × 10-6
-BARSIC- [3]
B. 4.75 × 10-4 is the answer
6 0
3 years ago
For double-helix formation, DG can be measured to be 2 54 kJ mol 1 ( 2 13 kcal mol 1 ) at pH 7.0 in 1 M NaCl at 25 8C (298 K). T
levacccp [35]

Answer:

ΔS = -661.0J/mol is the entropy change for the system

ΔS = -842J/mol.K is the entropy change for the surroundings

Explanation:

From the relationship between ΔG, T, ΔH and ΔS,

Mathematically, ΔG = ΔH - TΔS

TΔS = ΔH - ΔS

ΔS = ΔH - ΔS / T

but ΔG = -54 kJ/mol, ΔH = -251 kJ/mol and T = 25 °C (298 K)

plugging into the equation,

ΔS = -251 kJ/mol - ( -54 kJ/mol) / 298

ΔS  = -0.6610KJ/mol or in J.mol

ΔS = -661.0J/mol is the entropy change for the system

  • For entropy change for the surroundings = ΔS = ΔH/T
  • ΔS  = -251 kJ/mol / 298K
  • ΔS = -0.84KJ/mol.K or -842J/mol.K is the entropy change for the surroundings
8 0
3 years ago
Calculate the freezing point of the solution containing 0.105 m k2s. calculate the boiling point of the solution above. -g
Licemer1 [7]
Quantity of K2S m = 0.105 m 
Number of ions i = 2(K) + 1(S) = 3
 Freezing point depression constant of water Kf = 1.86 
delta T = i x m x Kf = 3 x 0.105 x 1.86 = 0.586
 Freezing point = 0 - 0.586 = 0.586 C
 Boiling point constant of water Kb = 0.512
 delta T = i x m x Kb = 3 x 0.105 x 0.512 = 0.161
 Boiling point = 100 + 0.161 = 100.161 C
5 0
3 years ago
Read 2 more answers
Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are
sertanlavr [38]

Answer:

Reaction A and B are unfavorable.

Explanation:

Gibbs free energy is an energy which that can be use to convert into useful work.

ΔG°=ΔH°-TΔS°

ΔG°= Gibbs free energy

ΔH° =  enthalpy of reaction

T = temperature of eh reaction

ΔS° = Entropy change

  • If the Gibbs  free energy of the reaction is positive than the reaction will be non spontaneous and the chemical reaction will be not feasible.
  • If the Gibbs  free energy of the reaction is negative than the reaction will be spontaneous and the chemical reaction will be feasible .

According to given information in the question:

Reaction A and B are non spontaneous as their Gibbs free energy value is positive.hence both are unfavorable.

3 0
3 years ago
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