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nexus9112 [7]
2 years ago
5

Calculate the mass of NaCO3 used in experiment. SHOW WORK — 15 points!!

Chemistry
1 answer:
Liono4ka [1.6K]2 years ago
5 0

The mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

<h3>Calculating mass </h3>

From the question we are to calculate the mass of NaHCO₃ (sodium bicarbonate) used in the experiment

From the given information

Mass of empty evaporating dish = 46.233g

Mass of evaporating dish + Sodium bicarbonate = 48.230g

∴ Mass of sodium bicarbonate (NaHCO₃) = [Mass of evaporating dish + Sodium bicarbonate] - [Mass of empty evaporating dish]

Mass of sodium bicarbonate (NaHCO₃) = 48.230g - 46.233g

Mass of sodium bicarbonate (NaHCO₃) = 1.997 g

Hence, the mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

Learn more on Calculating mass here: brainly.com/question/15268826

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state the formula for potassium hydroxide and explain, in terms of charges, how you formed the formula
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Potassium oxide is an ionic compound. The potassium has a charge of <span>K+</span> and oxygen has a charge of <span>O<span>2−</span></span>. We need 2 potassium ions to balance one oxide ion making the formula <span><span>K2</span>O</span>.

Potassium hydroxide is an ionic compound. The potassium has a charge of <span>K+</span> and hydroxide has a charge of <span>OH−</span>. We need 1 potassium ion to balance one hydroxide ion making the formula KOH.

<span><span>K2</span>O+<span> H2</span>O→KOH</span>

To balance the equation we place a coefficient of 2 in front of the potassium hydroxide.

<span><span>K2</span>O+<span>H2</span>O→2KOH</span>

I hope this was helpful.

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<h3>What is a nuclear fission reactor?</h3>

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Therefore, the option that involves the splitting of atoms into smaller ones is as follows: 235/92 U + 1/0n 94/36Kr + 139/56 Ba + 3/0n.

Learn more about nuclear fission reactor at: brainly.com/question/10203508

#SPJ1

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