Probably y = 8x. 56 = 8(7), so that works. Without more data, I couldn't say if it could be something else, so that's what I go with.
Answer:
6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.
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In an ecological study, the sampling mean proportion is 0.28 and the sample size is 50. a) What is the margin of error with a confidence level of 95%?
The solution to a system of two linear equations is (4, -3). One equation has a slope of 4. The slope of the other line is the negative reciprocal of the slope of the first. The system described above is represented by the following equations: y --X-2 y - 4x - 19 Please select the best answer from the choices provided
