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slavikrds [6]
3 years ago
8

A family’s lunch bill is $10.19 before tax and tip. Using the percents shown for sales tax and gratuity, how much money should t

he family pay if the gratuity is calculated after tax?
$11.80
$12.16
$12.28
$12.36
Mathematics
2 answers:
svp [43]3 years ago
7 0

Answer:

The answer is 12.36

Step-by-step explanation:

I just did the assignment and guessed and got them wrong and it said this is the right answer so yeah.

You're welcome!! :D

Nitella [24]3 years ago
3 0

Answer:

$12.36

Step-by-step explanation:

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Which is the most accurate way to estimate 26% of 91?
notka56 [123]

Answer:

B

Step-by-step explanation:

26% is close to 25%, which is equal to 1/4th.

You're adding to the number and removing from the percentage so it balances it out.

8 0
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3/11 ÷ 3/11<br>and <br>9/10 ÷ 3/5<br><br>PLZ HELP ME<br>​
mafiozo [28]

Answer:

3/11 divided by 3/11 is 1

9/10 divided by 3/5 is 1 1/2 (1.5)

Step-by-step explanation:

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53 - 2(3)
53 - 6
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3 years ago
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5. A survey of student pizza preferences showed that 43 students preferred cheese, 56 preferred sausage, 39 preferred pepperoni,
cestrela7 [59]

Answer:

P (Cheese) = 0.199, P (Sausage) = 0.259, P (Pepperoni) = 0.181,

P (Supreme) = 0.130, P (Another Kind) = 0.144

and P (Does not like any kind) = 0.088

Step-by-step explanation:

Given:

Number of students who prefer cheese = 43

Number of students who prefer sausage = 56

Number of students who prefer pepperoni = 39

Number of students who prefer supreme = 28

Number of students who prefer another kind = 31

Number of students who did not like any kind = 19

∴ The total number of students surveyed = 43+56+39+28+31+19=216       The number of students who prefer pizza = 43+56+39+28+31=197

The probability that a students likes pizza is,

P(Student\ likes\ pizza)=\frac{No.\ of\ students\ who\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                     =\frac{197}{216} \\=0.912

The probability that a students does not likes pizza is,

P(Student\ does\ not\ likes\ pizza)=\frac{No.\ of\ students\ who\ does\ not\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                                   =\frac{19}{216} \\=0.088

The probability distribution of students who prefer different kinds of pizza is:

  • The probability that a student likes cheese:

       P(A\ Student\ prefers\ cheese)=\frac{No.\ of\ students\ who\ prefer\ cheese}{Total\ no.\ of\ students\ surveyed}

                                                       =\frac{43}{216}\\=0.199

  • The probability that a student likes sausage:

        P(A\ Student\ prefers\ sausage)=\frac{No.\ of\ students\ who\ prefer\ sausage}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{56}{216}\\=0.259

  • The probability that a student likes pepperoni:

       P(A\ Student\ prefers\ pepperoni)=\frac{No.\ of\ students\ who\ prefer\ pepperoni}{Total\ no.\ of\ students\ surveyed}  

                                                             =\frac{39}{216}\\=0.181

  • The probability that a student likes supreme:

       P(A\ Student\ prefers\ supreme)=\frac{No.\ of\ students\ who\ prefer\ supreme}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{28}{216}\\=0.130

  • The probability that a student likes another kind:

        P(A\ Student\ prefers\ another\ kind)=\frac{No.\ of\ students\ who\ prefer\ another\ kind}{Total\ no.\ of\ students\ surveyed}

                                                                   =\frac{31}{216}\\=0.144

Thus, the probability distribution table is displayed below:

6 0
3 years ago
Simplify the expression:<br> 3j–1+4
RUDIKE [14]

Answer:

3j/3—5/3

J=5/3

hope helps

5 0
2 years ago
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