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Anestetic [448]
2 years ago
12

The dot plots below show the test scores of some mathematics students and some science students: Two dot plots are shown one bel

ow the other. The top and the bottom plots have the title Mathematics Students and Science Students respectively. Below the line for each dot plot is written Mark. The markings on each line are from 30 to 50 at intervals of 1. For the top plot there are two dots each for 34 and 40 and 1 dot each for 32, 33, 35, 37, and 39. For the bottom plot there are 2 dots each for 43, 46 and 49 and 1 dot each for 41, 42, and 47. Based on visual inspection of the dot plots, which group of students appears to have the larger average score?
Mathematics
1 answer:
ohaa [14]2 years ago
8 0

Answer:

Science students

Step-by-step explanation:

MATHEMATICS :

Plot interval = 30 to 50

MEAN :

(34*2) + (40*2) + (32*1) + (33*1) + (35*1) + (37*1) + (39*1) = 324

Sample size, n = (2 + 2 + 1 + 1 + 1 + 1 + 1) = 9

Mean = 324 / 9 = 36

BOTTOM :

SCIENCE :

MEAN : (43*2)+(46*2)+(49*2)+(41*1)+(42*1)+(47*1) =

406

SAMPLE SIZE = (2 + 2 + 2 + 1 +1 +1) = 9

406 / 9 = 45.111

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Answer:

480 cubic cm.        

Step-by-step explanation:  

We have been given that a wedge of cheese in he shape of a triangular prism has lengths of 10 cm, 13 cm, and 13 cm for its triangular sides. The perpendicular distance from the 10 cm side to the point of the wedge is 12 cm. The height of the wedge is 8 cm.  

\text{Volume of triangular prism}=\text{Base area*Height of the wedge}

We can see from our attachment that base of our triangular face is 10 cm and height of the triangular face is 12 cm and height of wedge is 8 cm.

Substituting these values in volume formula we will get,

\text{Volume of cheese wedge}=\frac{1}{2}*\text{10 cm*12 cm*8 cm}

\text{Volume of cheese wedge}=\text{5 cm*12 cm*8 cm}

\text{Volume of cheese wedge}=480\text{cm}^3

Therefore, the volume of cheese wedge will be 480 cubic cm.  

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A regular octagon with sides of length 8 and an apothem of length 9.66 has an area of _____ square units
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Answer:

Hope it help you

Stayhomestaysafe

Plz mark my answer brainliest✍️✍️

Step-by-step explanation:

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Q1) We have the following statements:

<span>1. Circle W has center (−3, 0) and radius 8.

We can write this statement as the following equation:

</span>(x-h)^2+(y-k)^2=r^2 \therefore (h,k)=(-3,0) \ and \ r=8 \\ \\ \therefore (x+3)^2+y^2=64
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The graph of this equation is shown in Figure 1.

</span><span>2. Circle V is a translation of circle W, 2 units down.

To do this translation we add two units to the y-coordinate, so:

</span>(x+3)^2+(y+2)^2=64
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The graph is shown in Figure 2.

</span><span>3. Circle V is a dilation of circle W with a scale factor of 2.

To do this dilatation we multiply both the center and the radius by the scale factor of 2, thus:

</span>(x+3)^2+y^2=64 \\ (h,k)=(-3,0) \\ (h_v,k_v)=2\times (-3,0)=(-6,0) \ and \ r_v=8\times2=16 \\ \\ (x+6)^2+y^2=256
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This circle is shown in Figure 3

So let's analyze each statement.

Q1.1) </span><span>The center of circle V is (−5, 0).

This is false. From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0).

Q1.2) 
</span><span>Circle V and circle W are similar.

Since all circles have the same shape even though they may be different sizes, then all circles are similar. Therefore, it is true that circle V and circle W are similar.

Q1.3) 
</span><span>The radius of circle V is 16.

From the statement 3 we can affirm that this is true. By applying the dilatation </span><span>with a scale factor of 2 we find out that the radius of the new circle is in fact equal to 16.

Q1.4) </span>Circle V and circle W have the same center. 

From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0). On the other hand, the center of circle W is (-3, 0). From this, it follows that this statement is false.

Q2) Suppose x is any positive number.

We have two concentric circles as follows:

x\ \textgreater \ 0 \\ \\ Circle \ 1: Center \ (0,0) \ and \ radius \ 2x \\ \\ Circle \ 2: Center \ (0, 0) \ and \ radius \ 10x<span>

Q2.1) Why is circle 1 similar to circle 2?
</span><span>
If we perform a dilatation, that is, a </span>resizing of one circle, centered on the shared center, until both circles overlap, it will be true that the circles will always overlap no matter what size they are, thus, they are similar. In fact, as we said in above all circles are similar. 

Q2.2) 
<span>Circle 2 is a dilation of circle 1 with a scale factor of 0.2.

Suppose that:

</span>x=2
<span>
Then circle 1 is given by the following equation:

</span>x^2+y^2=4
<span>
If we dilate this circle </span><span>with a scale factor of 0.2 then:

</span>Circle \ 1: x^2+y^2=4 \\ Diameter \ 1=2r=2\times 2=4 \\ \\ (h,k)=(0,0) \\ (h_v,k_v)=0.2\times (0,0)=(0,0) \ and \ r_v=0.2\times 2=0.4 \\ \\ Circle \ 2:x^2+y^2=0.16 \\ Diameter \ 2=2\times 0.4=0.8 \\ \\ So: \\ \\ Diameter \ 1 \neq Diameter \2
<span>
So the statement b</span>oth circles have congruent diameters is false.

<span>Q2.3) Circle 2 is a dilation of circle 1 with a scale factor of 5.

We have the same equation for circle 1:

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Circle \ 1: x^2+y^2=4 \\ \\ Dilatation: \\ (h,k)=(0,0) \\ (h_v,k_v)=5\times (0,0)=(0,0) \ and \ r_v=5\times 2=10 \\ \\ Circle \ 2:x^2+y^2=100

Two circles have the same area if they have the same radius. Given that this is no applied to our circles, the statement circle 1 and circle 2 have equal areas is false.

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3 years ago
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