Parallel Lines Cut by a Transversal: Maze

Mathematics

1 answer:

CaHeK987 [17]3 years ago

7 0

Start from Start Here square, the pointer to the next question to resolve is given by the solution to the equation in the current square

The values of the Maze are as follows;

x = 10
x = 8
x = -9
x = 5
x = 11
x = 3
x = -5
x = 9
x = 7
x = -7

Reason:

The solutions are;

10·x + 15 = 12·x - 5 by alternate interior angles theorem

∴ x = 10

6·x + 6 = 5·x + 14 by alternate exterior angles theorem

∴ x = 8

x + 109 = 100 by corresponding angles theorem

∴ x = -9

11·x + 5 + 120° = 180° by same side interior angles theorem

∴ x = 5

11·x - 1 = 10·x + 10 by corresponding angles theorem

∴ x = 11

35·x + 5 = 110 by corresponding angles theorem

∴ x = 3

x + 85 + x + 105 = 180 by same side interior angles theorem

∴ x = -5

7·x - 3 + 12·x + 12 = 180° by same side interior angles theorem

∴ x = 9

19·x - 3 = 130 by alternate interior angles theorem

∴ x = 7

x + 67 = 60 by alternate interior angles theorem

x = -7

Learn more here:

brainly.com/question/10623667

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