For this case what you can do is factorize the <span>polynomial equation</span>, which would be left like follows
x ^ 3 + x ^ 2 + 9x + 9 = 0
(x + 1) (x ^ 2 + 9) = 0
Resolving, we have that the missing root is
x = -1
Answer
x=-1
Shawndra is correct
She made two statements, and both are true:
1. It is not possible to draw a trapezoid that is a
rectangle.
This is true because a trapezoid<span> is a quadrilateral that has exactly one pair of
parallel sides, whereas a rectangle is a parallelogram (i.e. it has two
pairs of parallel sides)</span>
2. It is possible to draw a square that is a rectangle.
This is true because a rectangle refers to any parallelogram
with right angles. A square is also a parallelogram (has two pairs of opposite
sides) with right angles. In fact, all squares are rectangles; only that they
are a special kind of rectangle, where all the sides are equal in length.
Answer:
Yes
Step-by-step explanation:
All of these numbers are real numbers. None of them are complex numbers or irrational like <em>i</em>, s the answer is yes.
I have provided a chart to help you out with this topic.
Hope this helps! :)
So basically you just need to do the Pythagorean theorem to find the sides of the shaded rectangle, with c being the length of the side.
Small side:
2^2 + 6^2 = c^2
4 + 36 = c^2
40 = c^2
C is similar to 6.32456
Long side:
12^2 + 4^2 = c^2
144 + 16 = c^2
160=c^2
C is similar to 12.64911
And then you just multiply!
Ok so since we don't know how many cubes are covered, I will solve for how much area was covered on 1 cube
cube has 6 faces, all squares
area of square=side^2
therefor surface area (area covered by carmael)=6 times side^2
side=1 and 1/3
convert 1 and 1/3 to imporoper
1 and 1/3=1+1/3=3/3+1/3=4/3
Surface Area=6 times side^2
SA=6(4/3)^2
SA=6(16/9)
SA=96/9
SA=10 and 6/9
SA=10 and 2/3
answer is 10 and 2/3 in^2 is covered per cube
(if you are given a number of cubes, multiply 10 and 2/3 in^2 by number of cubes)
