So,
There are two transactions in Ramon's account. He first withdraws $140 (the check) and then deposits $268. We can write this as an expression.
2340 - 140 + 268
Simplify.
2200 + 268
2468
Ramon has $2468 left in his checking account.
The Answer is b The numerical values of the circumference and area are equal.
A graph is a way to represent a lot of data in a visual format. thus the number of games in the category 51-57 are 3.
<h3>What is a graph?</h3>
A graph is a way to represent a lot of data in such a visual format that it is easy for the user to understand the complete information in one go. the line of the graph is a function that follows the graph.
The categories and the data points can be arranged as;
51 - 57 = 51, 56, 55
58 - 64 = 63, 59, 60, 64
65 – 71 = 70, 67
72 or more = 75
Therefore, the number of games in the category 51-57 are 3.
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Answer:
Step-by-step explanation:
- Initial amount of drug = 50 mg
- Remains after each hour = 85%
- Time = t
<u>This relationship can be shown as a function:</u>
<u>After 4 hours remaining drug in blood:</u>
- y(4) = 50(0.85)^4 = 50(0.522) = 26.10 mg
Answer:
0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Sent by ABC Speedy Delivery Service.
Event B: Arrived on time.
The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.
This means that
The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.
This means that
Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
This is . So
0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.