100. When rounding to the hundreds place, you must consider the value of the digit in the tens place. If the digit in the tens place is 5 or greater, the digit in the hundreds place increases by 1. If the digit in the tens place is 4 or less the digit in the hundreds place remains the same. In this case, the number in the hundreds place was originally zero.
Answer:
6.14125(0.15) = 0.9211875 (below 1)
6.14125 - 0.92118 = 5.22007
Step-by-step explanation:
Given data
1. 10(.15)=1.5
2. 10-1.5=8.5
3. 8.5 (.15)=1.275
4. 8.5-1.275=7.225
continuation the sequence
5) 7.225 (0.15) = 1.08375
6) 7.225 - 1.08375 = 6.14125
7) <u> 6.14125(0.15) = 0.9211875 (below -one)</u>
8 ) <u> 6.14125 - 0.9211875 = 5.2200625 (get number 5)</u>
9) 5.2200625(0.15) = 0.783009
10) 5.2200625 - 0.783009 = 4.4370532
Answer:
( 4, 1 )
Step-by-step explanation:
midpoint formula: (x1 + x2/ 2, y1 + y2/ 2)
(9-1/ 2, -6+8/ 2) -> (4,1)
Answer:
Step-by-step explanation:
Method #1
We can draw a <em>right triangle</em> on the graph upon where the points are located and use the Pythagorean Theorem:
* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.
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Method #2
Or, we can use the Distance Formula:
![\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-x_1%20%2B%20x_2%5D%5E%7B2%7D%20%2B%20%5B-y_1%20%2B%20y_2%5D%5E%7B2%7D%7D%20%3D%20D)
[2, 7] [3, −3]
![\sqrt{[-3 + 2]^{2} + [3 + 7]^{2}} = D](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-3%20%2B%202%5D%5E%7B2%7D%20%2B%20%5B3%20%2B%207%5D%5E%7B2%7D%7D%20%3D%20D)
![\sqrt{[-1]^{2} + 10^{2}} = D](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-1%5D%5E%7B2%7D%20%2B%2010%5E%7B2%7D%7D%20%3D%20D)
** You see? It does not matter which method you choose, as long as you are doing the work correctly.
I am delighted to assist you anytime.
