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3 years ago

Help yall pls! !!!!!

Mathematics

1 answer:

Anika [276]3 years ago

7 0

Answer:

20 stickers

Step-by-step explanation:

sine she gave 20 to core one and wants to give the same amount to core two, she'd just give both core one and two 20 and then be left with 10

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A computer system password requires five characters, all lowercase letters (remember there are 26 letters), and all the letters

Goshia [24]

26 divided by 5 = 5.2

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3 years ago

A pair of dice is rolled. Find the probability for P(not 2 or not 12)

irakobra [83]

Answer:

There’s only one way to get 12 when 2 dice are tossed, both have to equal 6. There are 6 ways tossing a single die can come out (1,2,3,4,5,6), so if you toss dice, the second die could have any one of six values with each of the numbers that could result from the first toss (e.g., 1 from die 1 and 1,2,3,4,5, or 6 from die 2). So, considering there are 6 ways to fill each of two slots, there are 6 x 6 = 36 possible outcomes of tossing two dice. Only one of them equals 12, so p(12 given 2 dice tossed) = 1/36 = 0.02777777777778.

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3 years ago

A report describes the results of a large survey involving approximately 3500 people that was conducted for the Center for Disea

lesya692 [45]

0.3 - 60 is your right answer!

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3 years ago

Question is on the photo pls help

Bond [772]

Answer:

d)-8

Step-by-step explanation:

-6s-¹t²
-6(3)-¹(-2)²
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4 0

3 years ago

A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,

kenny6666 [7]

Answer:

(b) $\frac{1}{2}$

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

$\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}$

b. The mean of the sampling distribution

$\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}$

c. No; the proportion of males is $\frac{1}{4}$ while the mean is $\frac{1}{2}$ .

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0

3 years ago