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FinnZ [79.3K]
3 years ago
7

9x^3y^6/xy^6 Solve using only positive exponents

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

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What is 5.193 rounded to the nearest hundredth
saul85 [17]

Answer:

5.19

Step-by-step explanation:

3 rounds down to 0

5.190

5.19 is to the 100th

7 0
3 years ago
Read 2 more answers
Can someone thoroughly explain this implicit differentiation with a trig function. No matter how many times I try to solve this,
Anton [14]

Answer:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

Step-by-step explanation:

So we have the equation:

\tan(x-y)=\frac{y}{8+x^2}

And we want to find dy/dx.

So, let's take the derivative of both sides:

\frac{d}{dx}[\tan(x-y)]=\frac{d}{dx}[\frac{y}{8+x^2}]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[\tan(x-y)]

We can use the chain rule, where:

(u(v(x))'=u'(v(x))\cdot v'(x)

Let u(x) be tan(x). Then v(x) is (x-y). Remember that d/dx(tan(x)) is sec²(x). So:

=\sec^2(x-y)\cdot (\frac{d}{dx}[x-y])

Differentiate x like normally. Implicitly differentiate for y. This yields:

=\sec^2(x-y)(1-y')

Distribute:

=\sec^2(x-y)-y'\sec^2(x-y)

And that is our left side.

Right Side:

We have:

\frac{d}{dx}[\frac{y}{8+x^2}]

We can use the quotient rule, where:

\frac{d}{dx}[f/g]=\frac{f'g-fg'}{g^2}

f is y. g is (8+x²). So:

=\frac{\frac{d}{dx}[y](8+x^2)-(y)\frac{d}{dx}(8+x^2)}{(8+x^2)^2}

Differentiate:

=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

And that is our right side.

So, our entire equation is:

\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

To find dy/dx, we have to solve for y'. Let's multiply both sides by the denominator on the right. So:

((8+x^2)^2)\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}((8+x^2)^2)

The right side cancels. Let's distribute the left:

\sec^2(x-y)(8+x^2)^2-y'\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy

Now, let's move all the y'-terms to one side. Add our second term from our left equation to the right. So:

\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy+y'\sec^2(x-y)(8+x^2)^2

Move -2xy to the left. So:

\sec^2(x-y)(8+x^2)^2+2xy=y'(8+x^2)+y'\sec^2(x-y)(8+x^2)^2

Factor out a y' from the right:

\sec^2(x-y)(8+x^2)^2+2xy=y'((8+x^2)+\sec^2(x-y)(8+x^2)^2)

Divide. Therefore, dy/dx is:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)+\sec^2(x-y)(8+x^2)^2}

We can factor out a (8+x²) from the denominator. So:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

And we're done!

8 0
3 years ago
Can you put these number from least to greatest?
Eva8 [605]

The correct order would be:

5/64 x 3, 1/16 x 3, 3/32 x 4, 11/64 x 4, 7/16 x 3, 3/4 x 2, 3/8 x 4, 1 7/8 x 4, 2.25 x 2, 1.5 x 4, 3 3/8 x 3, 3.75 x 3

First we have to take all of the numbers and do the multiplication. It's often easiest to turn them in to decimals so that you have a common form.

3/32 x 4 = 3/8 = .375

3/4 x 2 = 3/2 = 1.5

1 7/8 x 4 = 15/4 = 3.75

2.25 x 2 = 4.5

1.5 x 4 = 6

3/8 x 4 = 3/2 = 1.5

5/64 x 3 = 5/32 = .156

3.75 x 3 = 11.25

1/16 x 3 = 3/16 = .1875

7/16 x 3 = 21/16 = 1.31

3 3/8 x 3 = 81/8 = 10.125

11/64 x 4 = 11/16 = .687

Now we can use those to put in order.

5/64 x 3 = 5/32 = .156

1/16 x 3 = 3/16 = .1875

3/32 x 4 = 3/8 = .375

11/64 x 4 = 11/16 = .687

7/16 x 3 = 21/16 = 1.31

3/4 x 2 = 3/2 = 1.5

3/8 x 4 = 3/2 = 1.5

1 7/8 x 4 = 15/4 = 3.75

2.25 x 2 = 4.5

1.5 x 4 = 6

3 3/8 x 3 = 81/8 = 10.125

3.75 x 3 = 11.25

Which if you are looking for without the extra terms, you can check the answer at the top.

5 0
2 years ago
Fast-Food Bills for Drive-Thru Customers A random sample of 49 cars in the drive-thru of a popular fast food restaurant revealed
sergeinik [125]

Answer:

sample mean:: 17.92

ME = z*s/sqrt(n) = 1.8807*6.35/sqrt(47) = 1.7421

------------------------

Step-by-step explanation:

6 0
3 years ago
Square root of 243 please
mart [117]

Answer:

15.5884572681

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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