Please help I will mark brainliest

A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di

denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is $0.432\, \frac{m}{s^{2}}$

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , $V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}$

Now centripetal acceleration is given by

$a_c=\frac{V^{2}}{R}$

where $V= 4.0\frac{m}{s}$

$Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m$

$\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}$

Thus her centripetal acceleration during the turn at each end of the track is $0.432\, \frac{m}{s^{2}}$

4 0

4 years ago

Read 2 more answers

If triangle weighs 1 gram how much does a square weigh

AleksAgata [21]

Answer:

the answer should me 1.5 grams

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

a washer has an outside radius of 6cm and a hole of radius 28cm. calculate the area of the face of the washer ( give your answer

Cerrena [4.2K]

Answer:

the area of face of washer is 22cm sq

4 0

3 years ago

Assign two variables for each problem, and write the equations. Do not solve.

NemiM [27]

Price of boots is represented as x, price of tennis shoes is represented as y. x-y=44.38 x+y=196.12 Isolate x. (Or y, if you wanted to) x=y+44.38 x=196.12-y Set them equal to each other. y+44.38=196.12-y Solve for y. Then plug it in to either of the two original equations to find x. x=120.24 y=75.86 Note: This is assuming that the boots are more expensive than the tennis shoes. If the tennis shoes are more expensive than the boots, then the prices would be switched. I didn't find this clear in your question.

6 0

3 years ago

Find an equation of the plane orthogonal to the line

jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/dt (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩t ) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨x, y, z⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨x, y, z⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨x - 9, y - 6, z⟩ • ⟨7, -7, -6⟩ = 0

7 (x - 9) - 7 (y - 6) - 6z = 0

7x - 63 - 7y + 42 - 6z = 0

7x - 7y - 6z = 21

so that

a = 7, b = -7, c = -6, and d = 21

4 0

3 years ago