Using S = ut + 1/2gt², from rest, u = 0
S = 1/2gt², g ≈ 9.8 m/s²
S = <span>1/2 *9.8*3²
</span>S = 0.5<span> *9.8*3*3
</span>
<span>S ≈ 44.1 m</span>
<u>Answer:</u>
The correct answer option is P (S∩LC) = 0.16.
<u>Step-by-step explanation:</u>
It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.
So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.552 = P(S∩LC) / 0.29
P (S∩LC) = 0.552 × 0.29 = 0.16
Answer:
7/15 Hope it helps
Step-by-step explanation:
Answer:
6. 550
7. 70
Step-by-step explanation:
6. 16+28 = 44, 44*25 = 1100 divided by 2 = 550
7. 2.5+3+5.5 = 11, 11+3 = 14, 14*10 = 140 divided by 2 = 70