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Snezhnost [94]
4 years ago
9

If x represents any number in the first column witch expression can always be used to find the value of y in the second coloumn

x 1 2 3 4
Y 5 7 9 11
Mathematics
1 answer:
olga2289 [7]4 years ago
6 0
Set up an equation and solve, or find a common sequence.

We can set up an equation like so, using x = 1 as a base:

x(number) + (another number) = y

translate to:

1(x) + (number) = 5

The common difference is 2 for each y value, so let's use that as a multiplier:

1(2) + number = y
2 + x = 5
x = 3

So lets move up a step:
x = 2 and y = 7

We use 2 as our multiplier and 3 as our adder:
2(x) + 3 = y
2(2) + 3 = 7
4 + 3 = 7

Lets try one more case :
x = 4 and y = 11

2(4) + 3 = 11
8 + 3 = 11
11 = 11
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What is the range of f(x) = 3x + 9?
SOVA2 [1]

Step-by-step explanation:

there must be some additional information missing (like the domain of the function), because just as it is written here, the function f(x) would not have any limitations, and its range would be -infinity < y < +infinity.

so, it is impossible to tell you which answer option is correct.

because again, based on the given information, none of these options is correct.

8 0
3 years ago
Help me and i’ll mark you brainliest plus you get 20 points !!!!
Anton [14]

Answer:

Angle bisector

Step-by-step explanation:

Find the measure of the angle COA. By angle addition postulate,

m\angle COX=m\angle AOX+m\angle COA

From the diagram,

m\angle COX=80^{\circ}\\ \\m\angle AOX=40^{\circ},

then

80^{\circ}=m\angle COA+40^{\circ}\\ \\m\angle COA=80^{\circ}-40^{\circ}=40^{\circ}

Find the measure of the angle BOA. By angle addition postulate,

m\angle BOX=m\angle AOX+m\angle BOA

From the diagram,

m\angle BOX=60^{\circ}\\ \\m\angle AOX=40^{\circ},

then

60^{\circ}=m\angle BOA+40^{\circ}\\ \\m\angle BOA=60^{\circ}-40^{\circ}=20^{\circ}

Find the measure of the angle COB. By angle addition postulate,

m\angle COX=m\angle BOX+m\angle COB

From the diagram,

m\angle BOX=60^{\circ}\\ \\m\angle COX=80^{\circ},

then

80^{\circ}=m\angle COB+60^{\circ}\\ \\m\angle COB=80^{\circ}-60^{\circ}=20^{\circ}

This means, the measures of angles COB and BOA are the same and are equal half the measure of angle COA, so angles COB and BOA are congruent. This means, the ray OB is the angle bisector of angle COA

6 0
3 years ago
Evaluate the following expression when x = -5 and y = 25.
MA_775_DIABLO [31]

Answer:

0

Step-by-step explanation:

In the given expression, substitute -5 for x and 25 for y:

5|x|-y to the third power over x   becomes

   5|-5| - 25         25 - 25

 ------------------ = --------------   =  0

            -5                  -5

6 0
4 years ago
I REALLY NEED HELP!
madam [21]
X-6 = X+10 i believe that should be the equation
4 0
3 years ago
Read 2 more answers
Two straight lengths of wire are placed on the ground, forming vertical angles. If the measure of one of the four angles formed
vitfil [10]
We have
angle 1=72 degrees

see the attached picture to better understand the problem

we know that
<span>Vertical angles are congruent
</span>angle1=angle3 \\ angle2=angle4
<span>
and

adjacent angles are supplementary
</span>angle2+angle1=180 \\ angle3+angle4=180
<span>
if the measure of one of the angles is </span>72 degrees and straight lines equal 180<span> degrees you have to
subtract </span>72 from 180
so
angle 2=180-72 \\ angle 2=108 degrees

therefore
angle 3=amgle 1 \\ angle 3=72 degrees

angle 4=amgle 2 \\ angle 4=108 degrees

the answer is

the measures of the other three angles are
108, 108 and 72 degrees

5 0
3 years ago
Read 2 more answers
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