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3 years ago

What is the equation of the perpendicular bisector of CB?

Mathematics

1 answer:

Olegator [25]3 years ago

6 0

Answer:

equation for perpendicular bisector passing through CB is;

y=⁴/³– 5/30

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At Yo-Yo Yogurt, the scale says that Sara has 8 ounces of vanilla yogurt in her cup. Her father’s yogurt weighs 11 ounces. How m

saveliy_v [14]

Answer: $1 \frac{3}{16}\ lb$

Step-by-step explanation:

You know that Sara has 8 ounces of vanilla yogurt in her cup and her father’s yogurt weighs 11 ounces. Then, the total ounces of frozen yogurt they buy altogether is:

$total_{(ounces)}=8\ oz+11\ oz\\\\total_{(ounces)}=19\ oz$

The next step is to make the conversion from ounces to pounds.

You need to remember that:

$1\ lb=16\ oz$

Therefore:

$total_{(pounds)}=(19\ oz)(\frac{1\ lb}{16\ oz})=\frac{19}{16}\ lb$

This result expressed as a mixed number, is:

$total_{(pounds)}=1\frac{3}{16}\ lb$

8 0

4 years ago

Evaluate m = for for m = 1 and (x1, y1) = (0, 2) and (x2, y2) = (x, 0).

77julia77 [94]

We know that
the slope formula is
m=(y2-y1)/(x2-x1)
(x1,y1)=(0,2)
(x2,y2)=(x,0)
m=1-----> equation 1
m=(0-2)/(x-0)------> m=-2/x -----> equation 2

equate equation 1 and equation 2
1=-2/x------> multiply by x both sides------> x=-2

the point (x2,y2) is ----------> (-2,0)

3 0

4 years ago

Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di

quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0

3 years ago

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4 years ago

What is the value of a

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3 years ago