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3 years ago

Can U pls help with this number in the sequence

Mathematics

1 answer:

shtirl [24]3 years ago

7 0

Answer:

First one:

1², 2², 3² and so on (Square of 1,2,3,4,5,6,7.....)

Second one:

2, 13, 26, 41...

add 11, add 13, add 15 (add increasing odd numbers, beginning from 11)

Third one:

4, 14, 29, 49

+10, +15, +20 and so on (add the multiple of 5,beginning from 10)

Fourth one:

1, 8, 27, 64

1³, 2³, 3³, 4³ and so on(cube of 1,2,3,4,5,6,7.....)

Brainliest please

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Afina-wow [57]

Answer:

$x = -2$ or $x = -5$

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

$x^2 + 7x + 10 = 0$

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$x^2 + 7x = -10$

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

$x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = \dfrac{9}{4}$

Now we use the square root property, if

$x^2 = k$ , then

$x = \pm \sqrt{k}$

$x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}$

$x + \dfrac{7}{2} = \pm \dfrac{3}{2}$

$x + \dfrac{7}{2} = \dfrac{3}{2}$ or $x + \dfrac{7}{2} = -\dfrac{3}{2}$

$x = -\dfrac{4}{2}$ or $x = -\dfrac{10}{2}$

$x = -2$ or $x = -5$

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3 years ago

How do i solve this?

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Because you know the area and that the shape is a square... if the side length is "s"... to find "s" you would say...

s²=1.69

Take the root of both sides and...

s=1.3 km

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Can U pls help with this number in the sequence​

Can U pls help with this number in the sequence