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Amiraneli [1.4K]
3 years ago
9

You have $39 in cash, composed of the largest bills possible. What is the probability that a randomly chosen bill from the $39 w

ill not be a $1 bill?
a. 4/7
b. 1/2
c. 3/7
d. 4/8
Mathematics
2 answers:
spayn [35]3 years ago
6 0
C. 3/7 because it would be 1 twenty, 1 ten, 1 five and 4 ones
PtichkaEL [24]3 years ago
6 0

Answer:

c) 3/7

Step-by-step explanation:

there are a total of 7 bills:

1 - $20

1 - $10

1 - $50

4- $1

P(not $1) = 3/7

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There are 81 red, blue and yellow
wel

Step-by-step explanation:

Here Given

Total counters = 81

red counters are 9 more than the yellow ones.

And Yellow counter = blue counter

So let the Yellow counter be x and as blue counter and yellow counter are same then blue counter will be also x

And by the question

Red counter = 9 + x

Now

9 + x + x + x = 81

9 + 3x = 81

3x = 81 - 9

3x = 72

x = 72 / 3

Therefore x = 24

Now

Red counters = 9 + 24 = 33

Blue counters = 24

Yellow counters = 24

Hope it helped :)

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Answer:

sdcce

Step-by-step explanation:

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Answer:

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Didn’t multiply 5 and 2
6 0
3 years ago
Is x = -7, the solution to -11 + 2x = -26? Justify your answer in complete sentences.
Natali5045456 [20]
First of all, you can move the +2x to the other side:
-11 = -26 - 2x

Then you can move the -26 to the other side and then simplify:
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Then you can divide both sides by 2:
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Then you can flip the sides and the signs around:
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No, The answer is not -7, it is -7.5
Hope this helps! :)
4 0
3 years ago
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