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Ber [7]
3 years ago
12

Simplify by combining like terms:​

Mathematics
1 answer:
Romashka [77]3 years ago
5 0

9514 1404 393

Answer:

  -77k²m³

Step-by-step explanation:

The variable arrangement is the same for each term, so we simply combine their coefficients:

  k²m³ +22k²m³ -100k²m³ = (1 +22 -100)k²m³ = -77k²m³

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Hatshy [7]
Please, in the future, post just one problem at a time.

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The slope of that line is then  m = rise / run = ------------ = +2.
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8 0
4 years ago
Please help I'm stuck on these 2 problems would help so much!!<br><br> Thanks!
MrRa [10]
700 - 100 =600 she spent $600 worth of monthly payments. if there is 12 months in a year then 600 ÷ 12 = 50 so she spent $50 a month.
4 0
3 years ago
The table below shows the typical hours worked by employees at a company. A new employee is offered an annual salary of $37,000.
Mademuasel [1]

Answer:

Salaried pay is preferable for a new employee

Step-by-step explanation:

<u>As per table, hours worked per week:</u>

  • 0+ 8.5+ 9.5+ 7.5+ 8+ 8.5+ 4 = 46

<u>Employee gets paid for 46 hours per week:</u>

  • $40*14 + (46- 40)*$21 = $686

<u>Average yearly salary would be:</u>

  • $686/7*365 = $35770

<u>Comparing with annual salary, we see:</u>

  • $37000 > $35770

As we see, hourly employees get paid less, so the new employee should choose annual salary option

7 0
3 years ago
Barbara plotted an elevation below sea level on a number line and labeled it A. She plotted point B above o, a distance that is
stellarik [79]

Answer: Because Point A is negative and the same distance below 0 on the number line as Point B is above it, Point B is both positive and the opposite of Point A.




7 0
3 years ago
Read 2 more answers
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach
nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that \mu = 130, \sigma = 30

What score is necessary to reach the 75th percentile?

This is X when Z has a pvalue of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 130}{30}

X - 130 = 0.675*30

X = 150.25

A score of 150.25 is necessary to reach the 75th percentile.

7 0
3 years ago
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