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anzhelika [568]
2 years ago
9

2(x+3)^(2)+8=0 Solve.

Mathematics
1 answer:
olga2289 [7]2 years ago
7 0

Answer:

2i-3

Step-by-step explanation:

2(x+3)²=-8

(x+3)²=-4

x+3=2i

x=2i-3

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The length of a rectangular poster is 2 more inches than three times its width. The area of the poster is 33 square inches. Solv
laiz [17]

Answer:

Step-by-step explanation:

Area of the rectangle = 33 inches sq

Area of a rectangle (formula) = l*b

let the width be x

length = 2 inches + 3x = 2+3x

Area of the rectangle = l*b = 2+3x + x

33 inches sq = 2+3x + x

33 in sq = 2+4x

33/2 = 4x

16.5/4 = x

x = 4.125

width= <u>4.125 inches</u>

length = 2+3x = 2+3(4.125) = <u>14.375</u>

<u></u>

(unless your poster is 32 sq inches and you made a mistake, just replace 33 with 32 and solve it)

7 0
1 year ago
Write the first five terms of the arithmetic sequence. a4 = 22, a10 = 64
dedylja [7]
Hello :
the general term is : 
an = a1+(n-1)×d  
or : an = ap +(n-p)×d......d is common diffrence
let : n=10 and p= 4
a10 =  a4 +(10-4)×d
64 = 22 + 6d
6d =  42
d= 7
conclusion :
a4 = 22
a3 = 22-7=15
a2=15-7=8
a1= 8-7=1
<span>the first five terms : 1 , 8 , 15 , 22</span>

4 0
3 years ago
-3 3/7 * 2 1/2 Has o be in simplest form!
OverLord2011 [107]

Answer:

-8.57142857143

Step-by-step explanation:

-8.57142857143

6 0
3 years ago
Read 2 more answers
Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang
PolarNik [594]

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence  f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence  f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx  = 2x

since  d(fx))/dx  = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0
2 years ago
Read 2 more answers
The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers
Pavel [41]

The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers

two consecutive even integers: n, n+2

next two consecutive even integers n+4, n+6

n+(n+2) >= 7+1/2(n+4 +n+6)

combine like terms

2n+2 >= 7 +1/2(2n+10)

distribute 1/2

2n+2 >= 7+n+5

2n+2>= n+12

subtract n from each side

n+2>= 12

subtract 2 from each side

n>10

4 integers : 10, 12 ,14, 16

7 0
3 years ago
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