Answer:
Bottom left.
Step-by-step explanation:
In order for any of them to be the graph of a function you would need that given a value of x, you get no more than one value of y. Zero is fine, you just picked an x out of the domain.
In layman's terms it means that if you grab a ruler, a piece of paper, a pen, and you scan the graph moving the edge parallel to the y axis (ie, vertically) you are allowed to touch the graph only once. Top right is out. Bottom left is ok, bottom right is not: you have infinite points of contact in there.
Top left would be fine, if it wasn't for x = 1. In there you have two values marked with a solid dot. That makes it not the graph of a function.
Answer:
3×5×53
Step-by-step explanation:
You can use divisibility rules to find the small prime factors.
The number ends in 5, so is divisible by 5.
795/5 = 159
The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.
159/3 = 53 . . . . . a prime number,* so we're done.
795 = 3×5×53
_____
* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.
Answer:
Step-by-step explanation:
1) Step 4: Marc has converted radical form to exponent form
Step 5: He has evaluated the value of the radical
3)
![x = \sqrt[3]{8}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B8%7D)
Here, 3 is index and 8 is radicand.
Prime factorize 8 and for every 3 numbers we can take one number outside the radical
Solution:
![x = \sqrt[3]{2*2*2}\\\\x = 2](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%5C%5C%5C%5Cx%20%3D%202)
4) No,my equation does not have an extraneous solution.
My solution, satisfies the equation
Add 26 to each side of the equation !
Answer:
50
Step-by-step explanation:
all your doing is dividing 100 by 20 and u get 50
