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Anna007 [38]
3 years ago
13

Will make brainiest if someone solves this

Mathematics
2 answers:
natali 33 [55]3 years ago
5 0
It a i’m positive !!
tekilochka [14]3 years ago
4 0
ME too I got this right
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A tank is being filled with water at a rate of 5.5 gallons per
Sonja [21]

Arithmetic sqaure: a + (n-1) * d

<em>               </em><u><em>where "a" is the first term, "d" is the common difference</em></u>

Here given:

a = 10 gallons

d = 5.5 gallons

  • nth term: 10 + (n-1) * 5.5

<u>Solve for first 5 terms</u>:

10 + (1-1) * 5.5 = 10

10 + (2-1) * 5.5 = 15.5

10 + (3-1) * 5.5 = 21

10 + (4-1) * 5.5 = 26.5

10 + (5-1) * 5.5 = 32

first five terms: 10, 15.5, 21, 26.5, 32

6 0
2 years ago
Read 2 more answers
Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two
telo118 [61]

Answer:

8 cm , 9cm

Step-by-step explanation:

sum of any two sides >third side

difference of any two sides<third side

only 8 cm and 9 cm satisfies it

8+9=17>13

9-8=1<13

8 0
3 years ago
A job fair was held at the Student Union. 25% of the students who attended received job offers. Of all of the students at the jo
vovangra [49]

Answer:

A) Both events are not independent.

B) Both events are not mutually exclusive

C) 8.33%

D) 80%

Step-by-step explanation:

A) Both events are not independent. This is because, If B occurs it means that it is very likely that J will occur as well.

B) Both events are not mutually exclusive. This is because it is possible for both events J and B to occur at the same time.

C) we want to find the probability that Joe who is not a business student will receive the job offer.

This is;

P(J|Not B) = P(J & Not B)/P(Not B)

Now,

P(J & Not B) = P(J) – (P(B) × P(J | B))

25% of the students who attended received job offers. Thus; P(J) = 0.25

40% were from the College of Business. Thus;

P(B) = 0.4

Among the business students, 50% received job offers. Thus;

P(J|B) = 0.5

Thus;

P(J & Not B) = 0.25 - (0.4 × 0.5)

P(J & Not B) = 0.25 - 0.2

P(J & Not B) = 0.05

Since P(B) = 0.4

Then, P(Not B) = 1 - 0.4 = 0.6

Thus;

P(J|Not B) = 0.05/0.6

P(J|Not B) = 0.0833 = 8.33%

D) This probability is represented by;

P(B | J) = P(B & J)/P(J)

P(B & J) = (P(B) × P(J | B)) = (0.4 × 0.5) = 0.2

P(B | J) = 0.2/0.25

P(B | J) = 0.8 = 80%

5 0
2 years ago
Simple math, please help, have to turn in soon
mezya [45]

Answer:1

Step-by-step explanation:

8 0
3 years ago
Which of the following best forms the figure shown
Pachacha [2.7K]
Where is the picture? If you could add your picture I’d be glad to help you!! :)
4 0
3 years ago
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