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abruzzese [7]
3 years ago
12

PLEASE HELP ME I NEED THE ANSWER ASAP THANK YOU SO MUCH!!

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0
(3,1) is the answer
Ostrovityanka [42]3 years ago
6 0

dark blue is the answer

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An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y
Kay [80]

Answer:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

\bar X_{1}=14 represent the mean for sample 1 (younger)

\bar X_{2}=20 represent the mean for sample 2 (older)  

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=31 sample size for the group 2  

n_{2}=31 sample size for the group 2  

t would represent the statistic

System of hypothesis

We want to test if  that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=31+31-2=60  

Replacing the info given we got:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

6 0
3 years ago
A block of wood has a mass of 120g and a volume of 200cm3. What is the density of the wood?
ozzi
Density=mass/volume
given mass=120g and volume=200cm3
density=\frac{120g}{200cm^3}=\frac{3}{5} \space\ \frac{g}{cm^3} or abot 0.6


the density is 0.6 \space\ \frac{g}{cm^3}
3 0
4 years ago
Read 2 more answers
Keith, Jason, Alyssa and Monique each have 27 playing cards. How many card to they have in all?
gtnhenbr [62]

Answer: I think its 81 but i'm not that sure.

Step-by-step explanation:

8 0
3 years ago
Write the polynomial as a product.<br> xk-xy-x^2+yk
Kazeer [188]

Answer:

(k-x)(x+y)

Step-by-step explanation:

x×(k-x)+y×(k-x)

=(k-x)(x+y)

3 0
3 years ago
A french fry stand at the fair serves their fries in paper cones. The cones have a radius of 22 inches and a height of 66 inches
icang [17]

Answer:

The height of the new cones will be 16.5 inches.

Step-by-step explanation:

We know that,

The volume of a cone is,

V=\frac{1}{3}\pi r^2 h

Where, r is the radius of the cone,

h is the height of the cone,

In the original cone,

r = 22 inches,

h = 66 inches,

Thus, the volume would be,

V_1=\frac{1}{3}\pi (22)^2(66)

Also, for the new cone,

r = 44 inches,

Let H be the height,

So, the volume of the new cone would be,

V_2=\frac{1}{3}\pi (44)^2(H)

According to the question,

V_2=V_1

\implies \frac{1}{3}\pi (44)^2(H)=\frac{1}{3}\pi (22)^2(66)

\implies H=\frac{22^2(66)}{44^2}=(\frac{22}{44})^2\times 66 = \frac{66}{4}=16.5

Hence, the height of the new cones will be 16.5 inches.

7 0
3 years ago
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