(Problems 1b and 2b are cut off in the photo)
1a Problem:
(-3,1)
(-3,5)
(-7,1)
2a Problem:
(6,2)
(3,5)
(10,7)
*Psst, I need one more brainliest answer to rank up, so if you gave that to me, it would be very appreciated, thanks :)*
Answer:
The value to the given expression is 8
Therefore ![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D8)
Step-by-step explanation:
Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed
Given expression can be written as below
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3)
To find the value of the given expression:
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D%5Cfrac%7B%28%2810%5E4%29%285%5E2%29%29%5E3%7D%7B%28%2810%5E3%29%285%5E3%29%29%5E3%7D)
( By using the property (
)
( By using the property 
)
( By using the property 
)
( By using the property 
)
(By using the property 
)
( By using the property 
)
Therefore
Therefore the value to the given expression is 8
Start weight- 8.03
week 1 - 8.8
week 2 - 8.13
week 3 - 9.03
week 4 - 9.08
So, the Omar should weigh 9 pounds 8 ounces by the end of 4 weeks.
I hope this helped!
Answer:
Step-by-step explanation:
= [ 
- 
] ← evaluate for upper limit - lower limit
= ( 
- 
) - ( 
- 
)
= - 8 - 9 +
= 
- 17
=
Hello from MrBillDoesMath!
Answer:
40
Discussion:
A diagram is always appreciated!
Assuming that
mAOC = mAOB + mBOC =>
108 = (3x + 4) + (8x - 28) => combine common terms
108 = (3x + 8x) + (4 - 28 ) =>
108 = 11x - 24 => add 24 to both sides
132 = 11x =>
x = 132/11 = 12
So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40
Thank you,
MrB
