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abruzzese [7]
3 years ago
12

PLEASE HELP ME I NEED THE ANSWER ASAP THANK YOU SO MUCH!!

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0
(3,1) is the answer
Ostrovityanka [42]3 years ago
6 0

dark blue is the answer

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How do you write 16x-3y=3 in slope intercept form
serg [7]
Y=16/3 x -1

First, you minus both sides by 16x. This will get you -3y = 3 - 16x

Then, you divide both sides by -3. Hence on the right hand side you will get 3 - 16x over -3, which can be split into (-16x/-3) + (3/-3). By simplifying this you can get 16/3 x - 1.
6 0
3 years ago
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Spencer spent 4 hours doing chores over the weekend. If he spent 2/3
Troyanec [42]

Answer:

6 chores

Step-by-step explanation:

ok so,

4 hours=240minutes

2/3of an hour= 60×2/3

=40 minutes

so since one chore needs 40 minutes, then:

40/240= 6

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6 0
3 years ago
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(HELP ME ASAP PLEASE) In the following diagram, A || B.
vladimir1956 [14]

Answer:

m<6=77°

Step-by-step explanation:

Because the angles marked 3x+5 and 4x+7 are same side exterior angles, they are supplementary, meaning that

3x+5°+4x+7°=180°

7x+12°=180°

7x=168°

x=24°

Because the angles marked 6 and 3x+5 are corresponding angles, they are congruent, so:

<6=24*3+5

<6=77°

7 0
2 years ago
What is the value of x
Andru [333]
The answer to your question is 54 because you have to bring over 2 to 3 and it would be 1x then bring over 52 and add it to 2 = 54
8 0
3 years ago
A rectangular painting by Leonardo da Vinci measured 62cm along its diagonal. If the painting has a height of 42 cm how wide is
IRINA_888 [86]

ANSWER

45.6cm to the nearest tenth.

EXPLANATION

The diagonal of the rectangular painting is 62cm.

The height of the painting is 42 cm.

The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.

From the Pythagoras Theorem,

{w}^{2}  +  {42}^{2}  = {62}^{2}

{w}^{2} = {62}^{2} -  {42}^{2}

{w}^{2}  = 2080

{w} =  \sqrt{2080}

w = 4 \sqrt{130}

The width of the painting is 45.6cm to the nearest tenth.

4 0
3 years ago
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