Answer:
The values of and so that the two linear equations have infinite solutions are and , respectively.
Step-by-step explanation:
Two linear equations with two variables have infinite solution if and only if they are<em> linearly dependent</em>. That is, one linear equation is a multiple of the other one. Let be the following system of linear equations:
(1)
(2)
The following condition must be observed:
(3)
After some quick operations, we find the following information:
, ,
The values of and so that the two linear equations have infinite solutions are and , respectively.
the maximum weight the person can be is 245lbs
Answer:
The expression equal to the problem given is the last answer 3(x-2)(x+5)/2x(x-5).
Step-by-step explanation:
In order to solve the problem, you first need to factor your quadratic equations in order to simply the expression. Starting with 3x^2 +12x-15, we can factor that into 3(x+5)(x-1). 4x^2 +4x - 8 would factor to 4(x+2)(x-1). Between these simplified expressions, we can cancel out (x-1) from the numerator and denominator. For the next fraction, we can factor 2x^2 - 8 into 2(x-2)(x+2) and factor x^2 - 5x into x(x-5). When we see the factored fraction expressions side by side, we can then cross-simplify the 2 and 4 as well as the (x+2) from the denominator of the first fraction and the numerator of the other. This leaves us with a final combined expression of 3(x-2)(x+5)/2x(x-5).
2 * 4 then add 2, it would be 2*4 = 8 + 2 = 10
==> 10/4 simplify you get 5/2
Answer:
1020
Step-by-step explanation:
well, the first three significant figures stops at the 102, so round the 1023.4567 to a whole number which just becomes 1023
then, round the answer so you only have the 102, so you would round down since 4 or less, which 3 is less than 4, you round down, and you would get 1020
that last 0 is not a significant figure because it does not have a decimal point or any other number following after it--any 0s at the end of a number are not significant if there is no decimal point or other number after them.