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Serggg [28]
3 years ago
8

5) Does the graph show a function? *

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

I think

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If f (x) = 8(5x-2) find f -1 (x).
saw5 [17]

Step-by-step explanation:

f(x)=8(5x-2)

interchanging the role of x&y

x=8(5y-2)

  • x=40y-16
  • x+16=401y
  • y=(x+16)/40

f-1(x)=(x+16)/10

<h3>stay safe healthy and happy.</h3>
6 0
3 years ago
The distance, y, in miles, traveled by a car for a certain amount of time, x, in hours, is shown in the graph below:
Kazeer [188]
Answer: The correct answer is the last choice.

In the first segment of the trip, the car goes from 0 to 2 hours and the line is moving up. Therefore, it traveled for 2 hours.

In the second segment, the line went straight horizontal for 1 hour. That means the distance didn't change, in other words it didn't move.

In the last segment, it moved up again for 2 hours.
8 0
3 years ago
Triangle ABC and triangle PQR each have two sides whose lengths are 7 and an angle whose measure is 40. Are the triangles congru
Elena L [17]

No

Step-by-step explanation:

they could be but it doesnt say where the angle is so there isn't enough information to tell if they are congruent. answer is no

8 0
3 years ago
Find the value of the angle θ rounded to 1 DP.
kogti [31]

Answer:

Step-by-step explanation:

Sin 21 = \frac{opposite side}{hypotenuse}

Sin 21 = \frac{BC}{15}

0.3583 = \frac{BC}{15}

0.3583*15 = BC

BC = 5.3745 = 5.37 m

Tan ∅ = \frac{opposite side}{adjacent side}

Tan ∅ = \frac{4}{5.37}= 0.7448

∅ = tan⁻¹ (0.7448) = 36.67 = 36.7

5 0
3 years ago
given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta
lapo4ka [179]

Answer:

\cos{\theta} = \frac{\sqrt{15}}{4}

Step-by-step explanation:

For any angle \theta, we have that:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

Quadrant:

0 \leq \theta \leq \frac{\pi}{2} means that \theta is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1

\frac{1}{16} + (\cos{\theta})^{2} = 1

(\cos{\theta})^{2} = 1 - \frac{1}{16}

(\cos{\theta})^{2} = \frac{16-1}{16}

(\cos{\theta})^{2} = \frac{15}{16}

\cos{\theta} = \pm \sqrt{\frac{15}{16}}

Since the angle is in the first quadrant, the cosine is positive.

\cos{\theta} = \frac{\sqrt{15}}{4}

3 0
3 years ago
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