X/49 = 21/x
x^2 = 21(49) = 1029
x = √1029 = 32.1
x = 32.1
Answer:
Colin has <em>8 sheets </em>left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers = 
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

So, the answer is:
Colin has <em>8</em> <em>sheets </em>left for his third class.
Sa = 2pi r h + 2pi r²
= 1327.32 units squared
Exactly like the previous question you posted.
-3x² - 9x = 0
Divide each side of the equation by -3 :
x² + 3x = 0
Factor the left side:
x (x + 3) = 0
This is true if x=0 or if x=-3 .
60x9=540 I believe is the answer