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3 years ago

EMERGENCY PLEASE HELP

Mathematics

2 answers:

Drupady [299]3 years ago

8 0

Answer: v(t) = 5,000(1.03)t

Step-by-step explanation:

defon3 years ago

6 0

Answer:

5150

Step-by-step explanation:

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How do you solve -5(5x+7)

kherson [118]

Answer:

x=7

Step-by-step explanation:

5x%2B7=6x Start with the given equation.

5x=6x-7 Subtract 7 from both sides.

5x-6x=-7 Subtract 6x from both sides.

-x=-7 Combine like terms on the left side.

Divide both sides by -1 to isolate x.

x=7 Reduce.

3 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!! PLZ HELPPPP Two groups of students were asked how far they lived from their school. The table shows the

-Dominant- [34]

Answer:

Step-by-step explanation:

mean = average. to find it, add all terms, and then divide by the number of terms.

find the mean of group a:

(1+1.5+3+3.2+2.8+1.5+1.8+2.5+2.2)/9 = 2.16

find the mean of group b:

(2+2.5+3.2+3+1.8+2.4+3+1.5+1/8)/9 = 2.1694

group b is larger.

answer = b

5 0

3 years ago

F(x)=x^2-3x; Find f(-8)

Bumek [7]

F(x) = x^2 - 3x
f(-8) = (-8)^2 - 3(-8)
f(-8) = 16 - (-24)
f(-8) = 16 + 24
f(-8) = 40 (Answer)

Hope this helps

3 0

3 years ago

Find the critical numbers of the function f(x) = x6(x − 2)5.x = (smallest value)x = x = (largest value)(b) What does the Second

Marrrta [24]

Answer:

$a) x=0, x=\frac{12}{11}, x=2 \:$ b) The 2nd Derivative test shows us the change of sign and concavity at some point. c) At which point the concavity changes or not. This is only possible with the 2nd derivative test.

Step-by-step explanation:

a) To find the critical numbers, or critical points of:

$f(x)=x^{6}(x-2)^{5}$

1) The procedure is to calculate the 1st derivative of this function. Notice that in this case, we'll apply the <em>Product Rule</em> since there is a product of two functions.

$f(x)=x^{6}(x-2)^{5}\Rightarrow f'(x)=(f*g)'(x)\\=f'g+fg'\Rightarrow (fg)'(x)=6x^{5}(x-2)^{5}+5x^{6}(x-2)^{4} \Rightarrow 6x^{5}(x-2)^{5}+5x^{6}(x-2)^{4}=0\\f'(x)=6x^{5}(x-2)^{5}+5x^{6}(x-2)^{4}$

2) After that, set this an equation then find the values for x.

$x^{5}(x-2)^{4}[6(x-2)+5x]=0\Rightarrow x^{5}(x-2)^{4}[11x-12]=0\Rightarrow x_{1}=0\\(x-2)^{4}=0\Rightarrow \sqrt[4]{(x-2)}=\sqrt[4]{0}\Rightarrow x-2=0\Rightarrow x_{2}=2\\(11x-12)=0\Rightarrow x_{3}=\frac{12}{11}$

$x=0\:(smallest\:value)\:x_{3}=\frac{12}{11}\:x=2 (largest value)$

b) The Second Derivative Test helps us to check the sign of given critical numbers.

Rewriting f'(x) factorizing:

$f'(x)=(11x-12)(x-2)^4x^{5}$

Applying product Rule to find the 2nd Derivative, similarly to 1st derivative:

$f''(x)>0 \Rightarrow Concavity\: Up\\\\f''(x)$

$f''(x)=11\left(x-2\right)^4x^5+4\left(x-2\right)^3x^5\left(11x-12\right)+5\left(x-2\right)^4x^4\left(11x-12\right)\\f''(x)=10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)$

1) Setting this to zero, as an equation:

$10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)=0\\\\$

$10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)=0\\(x-2)^{3}=0 \Rightarrow x_1=2\\x^{4}=0 \therefore x_2=0\\11x^{2}-24x+12=0 \Rightarrow x_3=\frac{12+2\sqrt{3}}{11}\:,x_4=\frac{12-2\sqrt{3}}{11}\cong 0.78$