Question

Need help here plss

Answer 1

Step-by-step explanation:

In order to graph this system of equations, you have to put the equations in terms of y so that you can graph it by hand.

For the first equation:

$x+y$

Subtract x on both sides so that it reads to be $y$

For the second equation:

$3x-y\geq 4$

Subtract 3x on both sides and divide by -1 to make the y positive. Remember that when you divide, the sign $(\leq or \geq )$ always flips:

$-y\geq -3x+4\\y\leq 3x-4$

So the two equations you have to graph now are $y$ and $y\leq 3x-4$.

In order to graph, start from your y-intercept for each of the equations and go vertical/horizontal based on the coefficient of your equation. For instance, for your first equation, you would go down -1 and to the right 1. Repeat until your whole equation is graphed. For the second equation your coefficient is 3, so you would go up 3 from -4 and to the right 1. Repeat.

Once you have your equations graphed, you need to find where the two graphs both have solutions. To do this, pick any point from the graph and plug it into the x and y of one equation. If the equation equals itself, then that area is the solution of the graph for that equation. Make sure to do this for both equations. Once you find the area in which both equations have solutions for each other, that is the area that needs to be shaded.

Here is what your graph should look like: