3 consecutive even numbers that add up to 3000
1 answer:
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Answer:
The probability that he answered neither of the problems correctly is 0.0625.
Step-by-step explanation:
We are given that a student ran out of time on a multiple-choice exam and randomly guess the answers for two problems each problem have four answer choices ABCD and only one correct answer.
Let X = <u><em>Number of problems correctly answered by a student</em></u>.
The above situation can be represented through binomial distribution;
where, n = number of trials (samples) taken = 2 problems
r = number of success = neither of the problems are correct
p = probability of success which in our question is probability that
a student answer correctly, i.e; p = = 0.75.
So, X ~ Binom(n = 2, p = 0.75)
Now, the probability that he answered neither of the problems correctly is given by = P(X = 0)
P(X = 0) =
=
= <u>0.0625</u>
To solve the problem, simply plug in the value for x in both functions, as shown below:
-->
--->
-->
--->
---->
, so the answer is 34.