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Andrews [41]
3 years ago
11

Help me solve this problem please

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Step-by-step explanation:

nope guy but little you now

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If m (x) = StartFraction x + 5 Over x minus 1 EndFraction and n(x) = x – 3, which function has the same domain as (m circle n) (
Mars2501 [29]

Question:

If m (x) = StartFraction x + 5 Over x minus 1 EndFraction and n(x) = x – 3, which function has the same domain as (m circle n) (x)?

h (x) = StartFraction x + 5 Over 11 EndFraction

h (x) = StartFraction 11 Over x minus 1 EndFraction

h (x) = StartFraction 11 Over x minus 4 EndFraction

h (x) = StartFraction 11 Over x minus 3 EndFraction

Answer:

Option C: h(x)=\frac{11}{x-4} has the same domain as $(m \circ n)(x)$

Explanation:

It is given that m(x)=\frac{x+5}{x-1} and n(x)=x-3

Let us find the domain of $(m \circ n)(x)$

$\begin{aligned}(m \circ n)(x) &=m(n(x))\\&=m(x-3) \\ &=\frac{(x-3)+5}{(x-3)-1} \\ &=\frac{x+2}{x-4} \end{aligned}$

Now, let us equate the denominator equal to zero to determine the domain.

$x-4=0$

     x=4

Thus, the function becomes undefined at the point x=4

Hence, the domain of $(m \circ n)(x)$ is $(-\infty, 4) \cup(4, \infty)$

Now, we shall find the function which has the same domain as $(m \circ n)(x)$

Option A: h(x)=\frac{x+5}{11}

The function h(x) has the domain of set of all real numbers $-\infty

Thus, the interval (-\infty,\infty) is not the same domain as $(-\infty, 4) \cup(4, \infty)$

Hence, Option A is not the correct answer.

Option B: h(x)=\frac{11}{x-1}

Equating the denominator equal to zero, the function becomes undefined at the point x=1

Thus, the function h(x) has the domain of $(-\infty,-1) \cup(-1, \infty)$ is not the same domain as $(-\infty, 4) \cup(4, \infty)$

Hence, Option B is not the correct answer.

Option C: h(x)=\frac{11}{x-4}

Equating the denominator equal to zero, the function becomes undefined at the point x=4

Thus, the function h(x) has the domain of $(-\infty, 4) \cup(4, \infty)$ is the same domain as $(-\infty, 4) \cup(4, \infty)$

Hence, Option C is the correct answer.

Option D: h(x)=\frac{11}{x-3}

Equating the denominator equal to zero, the function becomes undefined at the point x=3

Thus, the function h(x) has the domain of $(-\infty,3) \cup(3, \infty)$ is not the same domain as $(-\infty, 4) \cup(4, \infty)$

Hence, Option D is not the correct answer.

4 0
3 years ago
1. Suppose y varies directly with x, and y = 14 when x = –4. What is the value of y when x = –6?
juin [17]
<span>1) y varies directly with x, then we have: y = kx,  k is the constant of variation 

y = kx

14 = - 4k
k = 14/- 4, or - 7/2, or - 3.5 

y = kx
y = - 3.5(- 6) 
y=21

2) </span><span>201.6 is the right answer.see the procedure used in Q1.

3) K = y/x
        = 9/12
        = 3/4</span>
7 0
4 years ago
Anyone know the answer?
Degger [83]

Answer:

D. 0

Step-by-step explanation:

plug in the values then solve 2^2=4 3-3=0 4×0=0

3 0
3 years ago
Read 2 more answers
The executive summary component of a business plan is to describe
exis [7]

Answer:

Executive summary describes the 'big picture behind your business, what your business has to offer the consumer, and why

Step-by-step explanation:

B is right

6 0
2 years ago
What expression is equivalent to 2(x+4)
Arte-miy333 [17]

Answer:

2x + 8

Step-by-step explanation:

solve by using the distributive property

2(x + 4) = (2)(x) + (2)(4)

2x + 8

5 0
3 years ago
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