Answer: 0.5
Step-by-step explanation: In this problem, we're asked to solve the following equation for <em>p. </em>Let's first switch 14 and 14p around so we have 14p + 14 = 21.
<em />
To solve this equation for <em>p</em>, we must first isolate the term containing <em>p</em> which in this case is 14p.
Since 14 is being added to 14p, we need to subtract 14 from both sides of the equation.
14p + 14 = 21
-14 -14
On the left side of the equation, the positive 14 and negative 14 cancel each other out and we have 14p. On the right side of the equation, we hav 21 - 14 which gives us 7.
Now we have the equation 14p = 7.
Since <em>p</em> is being multiplied by 14, to get <em>p</em> by itself, we divide both sides of the equation by 14.
On the left side of the equation the 14's cancel and we are left with <em>p</em>. On the right side of the equation, 7 divided by 14 is 0.5 which is our answer.
Therefore, p = 0.5 which is the solution for our equation.
Remember, you can always check your solution by substituting a number in for a variable to make sure the equation is true.
A (-4,5)
B (-3,1)
C (-5,2)
A'(3,1)
B'(2,5)
C'(4,4)
Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
152,000
is the correct answer
Answer:
bunches up in the middle and tapers off symmetrically at either end
Step-by-step explanation:
By definition a normal distribution is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.
Because the data towards the mean is more frequent in occurrence, the graph peaks at the center. The data occurs less frequently at the tail ends of the distribution, thus the shape of the distribution is a bell shape that peaks at the center and tapers off towards the tails. The key characteristic is that the distribution of data is perfectly symmetrical.
This is why the answer is:
The data depicted in a histogram show approximately a normal distribution if the distribution <u>bunches up in the middle and tapers off symmetrically at either end.</u>
