What you should do first is simplify the equation into the y = mx + b format. Move 2x to the other side. Know that in doing this, 2x must become the opposite of what it currently is (-2) in order for the equation to remain true. We also have to take away the '10' because the line is parallel, not exactly the same, which means a different y intercept. This looks like:
Next, simplify y to make things easier. This can be done by dividing both sides by 5, like so:
What you should also know is that if a line is parallel to another, then this means the slope has to be the same because they both have the same changes in rise and run. With this in mind, simply plug in the x and y values.
Add 2 to both sides to isolate b.
Which means that -2 = b.
Now that we have the y intercept, we can write the equation of the line, which is 
.
Hope this was helpful.
Answer is 5 sorry if I’m wrong
The starting weight of the radioactive isotope = 96 grams
Weight after one hour is half of the starting weight. So the weight of the radioactive isotope after 1 hour = 48 grams
After 2 hours the weight is half as compared to the weight after previous hour. So weight after 2 hours = 24 grams.
This means, after every hour the weight is being halved. The half life of radioactive isotope is one hour.
Since after every hour, the weight is being halved, the weight of the isotope can be modeled by an exponential equation.
So,
Initial Weight = W₁ = 96
Change factor = 1/2 = 0.5
The general equation of the sequence will be:
Here t represents the number of hours. Using various values of t we can find the weight of the radioactive isotope at that time.
We can plot the sequence using the above equation. The graph is attached below.
This is a GCF problem,
find the GCF of 36 and 27. To do this, list out the factors for each number.
EX 36- 1×36, 2×18, so on and so on. Then do this for 27. The GCF will be the greatest factor. In this case, that is 9.
So there would be 9 groups because that is the greatest common factor.
there would be 4 roses in each group because 4×9= 36.
There are 3 carnations in each group because 9×3 =27.
So 9 groups with 4 roses and 3 carnations.
False. When a quadrilateral has two sets of parallel sides ,like I drew below, all four corners form right angles.
