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avanturin [10]
2 years ago
7

Which pair shows equivalent expressions?

Mathematics
1 answer:
Mamont248 [21]2 years ago
3 0

Answer:

It's C

Step-by-step explanation:

When you multiply - 2 to what you have in the brackets you get - 2x - 10

Hope this helps, have a wonderful day

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A student wants to create a 2:1 scale drawing of the classroom. Is this an appropriate scale to use? Why or why not?
kvv77 [185]

Answer:

I don’t know figure it out

Step-by-step explanation:

7 0
2 years ago
This figure is made up of a rectangle and parallelogram.
ivann1987 [24]

The area of the figure is 40 units. (rounded off from 39.998 units)

Step-by-step explanation:

1. Area of the figure = Area of Rectangle + Area of Parallelogram.

2. Naming points:

Let the rectangle consist of points A(-6,-1), B(-5,-5), C(3,-3) and D(2,1).

Let the parallelogram consist of points C(3,-3), D(2,1), E(2,7) and F(3,3).

3. Each coordinate has a point on the x-axis and a point on the y-axis. We shall refer to these points as x', x'' ,x''' and so on corresponding to the x-axis values of A, B, C and so on in that order till F. For the y-axis points, we will name them in the series of y', y'', y''' and so on.

In simple words, in A(-6,1), x' = -6; y' = -1

4. Formula for finding area:

Area of a rectangle = length (l) × width (w)

Area of a parallelogram = base (b) x height (h)

5. Finding area of the rectangle:

l = AD = \sqrt{[x'''' - x']^{2} - [y'''' - y']^{2}}

, i.e. AD = \sqrt{[2 - (-6)]^{2} - [1 - (-1)]^{2}}

, i.e. AD = √68 = 8.246 (rounded to 3 decimals) = l

Now, w = AB = \sqrt{[x'' - x']^{2} - [y'' - y']^{2}}

, i.e. AB = \sqrt{[(-5) - (-6)]^{2} - [(-5) - (-1)]^{2}}

, i.e. AB = √17 = 4.123 (rounded to 3 decimals) = w

Area of rectangle = l x w = 8.246 x 4.123 = 33.998 units.

6. Finding area of the parallelogram:

b = DE = 6 units (we can observe this from the graph, i.e. points from 1 to 7 on the y axis)

h = Height is the line drawn perpendicular to the base from point F, which as we can see is 1 unit long.

Hence, Area of parallelogram = b x h = 6 x 1 = 6 units.

7. Now, adding both, we can arrive at the final answer.

Area of the figure = Area of rectangle + Area of parallelogram,

i.e. 33.998 units + 6 units = 39.998 units. (can be rounded off to 40 units)

4 0
3 years ago
PLEASE HELP BRAINLEST TO WINNER!!!!!!!
choli [55]

(-1, -5)

x-axis is to flip the y - coordinates

y-axis is to flip the x - coordinates

8 0
2 years ago
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Prove <br><br><br><br><img src="https://tex.z-dn.net/?f=%20%5C%5C%20" id="TexFormula1" title=" \\ " alt=" \\ " align="absmiddle"
irina1246 [14]

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5 0
3 years ago
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Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.
elena55 [62]

Answer:

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

Step-by-step explanation:

Given

f(b) = b^2 - 75

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

0 = b^2 - 75

Add 75 to both sides

75 + 0 = b^2 - 75 + 75

75 = b^2

Take square roots of both sides

\sqrt{75} = \sqrt{b^2}

\sqrt{75} = b

Reorder

b = \sqrt{75}

Expand 75 as a product of 25 and 3

b = \sqrt{25*3}

Split the expression

b = \sqrt{25} *\sqrt{3}

b = \±5 *\sqrt{3}

b = \±5 \sqrt{3}

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

The options are not clear enough; however the roots of the equation are b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

4 0
3 years ago
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