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3 years ago

PLEASEEEEEE HELP!! I WILL GIVE BRANLIEST TO CORRECT ANSWER

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

A = 3x^2 - 2x - 1

Step-by-step explanation:

3x times x equals 3x^2

(3x times - 1) + (x times 1) = -2x

1 times -1 = -1

put the partial products together, you get the above answer.

tekilochka [14]3 years ago

6 0

Use photomath it’s faster and you get correct Answers!<3 have a good day

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Dominick's puppy weighs 8 pounds and is gaining about 1 3/4 pounds each week, what's the rate of change

N76 [4]

Your rate of change would be 3/4 lb/week.
You could model this with a linear eq:

y = 8+ 3/4x

5 0

4 years ago

Find the unit price<br> 9 colored pencils for $2.88<br> $<br> per colored pencil

mrs_skeptik [129]

Answer:

32 cents per color pencil

Step-by-step explanation:

well well if you divide $2.88 into 9 you'll get 32 cents

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3 years ago

A ball is launched upward at 14 m/s from a platform 30 m high.Find the maximum height the ball will reach and how long it will t

BartSMP [9]

Answer:

The ball will reach a maximum height of 39.993 meters after 1.428 seconds.

Step-by-step explanation:

Let suppose that no non-conservative forces acts on the ball during its motion, then we can determine the maximum height reached by the Principle of Energy Conservation, which states that:

$K_{1}+U_{g,1} = K_{2}+U_{g,2}$ (1)

Where:

$K_{1}$ , $K_{2}$ - Initial and final translational kinetic energies, measured in joules.

$U_{g,1}$ , $U_{g,2}$ - Initial and final gravitational potential energies, measured in joules.

By definition of translational kinetic energy and gravitational potential energy we expand and simplify the expression above:

$\frac{1}{2}\cdot m\cdot v_{2}^{2}+m\cdot g\cdot y_{2}= \frac{1}{2}\cdot m\cdot v_{1}^{2}+m\cdot g\cdot y_{1}$ (2)

Where:

$m$ - Mass of the ball, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Initial and final speed of the ball, measured in meters per second.

$y_{1}$ , $y_{2}$ - Initial and final heights of the ball, measured in meters.

The final height of the ball is determined by the following formula:

$v_{2}^{2}+2\cdot g\cdot y_{2} = v_{1}^{2}+2\cdot g\cdot y_{1}$

$v_{1}^{2}-v_{2}^{2}+2\cdot g \cdot y_{1}=2\cdot g\cdot y_{2}$

$y_{2} = y_{1}+\frac{v_{1}^{2}-v_{2}^{2}}{2\cdot g}$ (3)

If we know that $y_{1} = 30\,m$ , $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , the maximum height that the ball will reach is:

$y_{2} = 30\,m + \frac{\left(14\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$y_{2} = 39.993\,m$

The ball will reach a maximum height of 39.993 meters.

Given the absence of non-conservative forces, the ball exhibits a free fall. The time needed for the ball to reach its maximum height is computed from the following kinematic formula:

$t = \frac{v_{2}-v_{1}}{-g}$ (4)

If we know that $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$t = \frac{0\,\frac{m}{s}-14\,\frac{m}{s} }{-9.807\,\frac{m}{s^{2}} }$

$t = 1.428\,s$

The ball will take 1.428 seconds to reach its maximum height.

6 0

3 years ago

Pls help math anser if your correct ok

N76 [4]

Answer:

6·(-5)

Step-by-step explanation:

-5= the change of gas per hour

6= total hours the bus has

If every hour the change of gas is -5 and theres a total of 6 hour then multiplication is involved. 6 hours would be positive not negative. This creating 6·(-5).

5 0

3 years ago

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“???” is a relationship between two variables where if one variable increases, the other one also increases.

ladessa [460]

Answer:

C. Positive Correlation

Step-by-Step explanation

Because a positive correlation is a relationship between two variables that move in tandem—that is, in the same direction.

7 0

3 years ago