Ask question

Ask question

All categories

3 years ago

15

Write an equation for the line that passes through (3,5) and (3,9). Is the line parallel or perpendicular to the x-axis? What is

the slope of the line?

1 answer:

iren [92.7K]3 years ago

8 0

Equation is x-3=0....

You might be interested in

If f(x)=2x^6-5x-1, then what is the remainder when f(x) is divided by x-2

Harrizon [31]

Answer:

117/(x-2)

Step-by-step explanation:

Symbolab

8 0

3 years ago

A number line going from negative 3 to positive 5. A closed circle is at negative 1.5. Everything to the left of the circle is s

kykrilka [37]

the inequality in the number-line is:

x ≤ -1.5

<h3></h3><h3>Which inequality is represented?</h3>

We know that we have a closed circle at -1.5, this means that the value is a solution of the inequality.

Then we have a line that goes to the left of that circle, so the inequality will have solutions that are less than or equal to -1.5

Then the inequality is:

x ≤ -1.5

If you want to learn more about inequalities:

brainly.com/question/24372553

#SPJ1

5 0

2 years ago

Draw the model to show 5.5/5

babunello [35]

This would be easy if you made more sense out of the question.

4 0

3 years ago

Use the long division method to find the result when x^3+7x^2+12x+6x 3 +7x 2 +12x+6 is divided by x+1x+1. If there is a remainde

Aliun [14]

Answer:

By long division (x³ + 7·x² + 12·x + 6) ÷ (x + 1) gives the expression;

$x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}$

Step-by-step explanation:

The polynomial that is to be divided by long division is x³ + 7·x² + 12·x + 6

The polynomial that divides the given polynomial is x + 1

Therefore, we have;

$\ \ \ \ \ \ \ \ \ \ \ \ x^2 + 5\cdot x + 7\\ (x + 1) \sqrt{x^3 + 7\cdot x^2 +12\cdot x + 6} \\\ {} \ {} \ {} \ \ {} \ {} \ {} \ {} \ {} \ {} \ {} \ \ x^3 + 2 \cdot x^2 \\\ \ \ \ {} \ \ {} \ {} \ {} \ \ {} \ {} \ \ \ {} \ {} \ {} \ \ {} \ {} \ {} \ \ 5 \cdot x^2 + 12\cdot x + 6\\ \ {} \ {} \ {} \ {} \ {} \ {} \ \ {} \ {} 5 \cdot x^2 + 5\cdot x\\\ 7\cdot x+6\\7\cdot x+7\\-1$

(x³ + 7·x² + 12·x + 6) ÷ (x + 1) = x² + 5·x + 7 Remainder -1

Expressing the result in the form $q(x) + \dfrac{r(x)}{b(x)}$ , we have;

$(x^3 + 7\cdot x^2 + 12 \cdot x + 6)\div (x + 1) = x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}$

4 0

3 years ago

Solve for 1/3(x+2)=2/3x+4

Norma-Jean [14]

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

1

3

(x+2)=

2

3

x+4

Answer:

x=−10

8 0

4 years ago