Ask question

Ask question

All categories

2 years ago

6

Fill in the blank to complete the equation below__ + 81 = 9(7+9)

2 answers:

Elis [28]2 years ago

5 0

Answer:

63

Step-by-step explanation:

9(7+9) = 63 +81

antoniya [11.8K]2 years ago

5 0

Answer:

Hi your answer is 144 i don't how i got but it is 144

You might be interested in

Two dice are rolled. Define the events as follows: A : sum of 7, B : doubles, C : sum of 8

love history [14]

Answer: for a sum of 7 would either be 6 and 1, 5 and 2 or 4 and 3. you can roll a double 1,2,3,4,5,6. the sum of 8 would be 2 and 6, 3 and 5 and a double 4,

Step-by-step explanation:

well the there are six sides on a die so 6 x 2 is 12 so the max sum you can get is 12. So you take 7 and you start adding up to 7, same thing for sum of 8. since there is 6 sides and a pair of dices you will roll six doubles

5 0

2 years ago

Can someone please help me with this question ASAP.It is due tommorrow.

ololo11 [35]

D. All irrational numbers are rational numbers.

I attached the diagram my teacher showed us when we learned about this. I think it makes it a lot less confusing.

Hope this helps :)

7 0

2 years ago

Read 2 more answers

Is 0.88 a terminating decimal

KengaRu [80]

Yes
hope this helped you

7 0

2 years ago

Read 2 more answers

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

2 years ago

At the begining of the year the wong family car had been driven 14,539 miles. At the end of the year , their car had been driven

Nuetrik [128]

Their family drove 7,305 miles that year. Hope this helps!!

8 0

3 years ago