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Marat540 [252]
3 years ago
6

Which line is parallel to y=3/4x+10

Mathematics
1 answer:
Alborosie3 years ago
5 0

The answer would be number 4, y=3/4x-6.

This is because both of the equations share the same slope of 3/4x.

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Your mailbox is 4 ft from a straight street. You pace between the mailbox and the street, such that the distance between you and
FrozenT [24]
You are moving in the path of a parabola.

The conic section  is parabolic - the street is the directrix  and the mailbox is the focus.
6 0
4 years ago
Help, Help, Help, Help, Help,
aniked [119]

Step-by-step explanation:

answer is in photo above

3 0
3 years ago
Read 2 more answers
Solve the equation below for x.
svetlana [45]
If x + y = 5 and 3x = 2 then what you
do is:
3x = 2 and since you want the variable by itself you’d divide by 3... giving you an answer of x = 2/3 BUT YOURE NOT DONE YET
so now you plug what x equals (2/3) into the equation x + y = 5:
2/3 + y = 5
to solve this you have to subtract each side by 2/3 so x = 5 - 2/3
(5/1 - 2/3.... to get like denominators multiply the nominator and the denominator for 5/1 by 3 giving you: 15/3 - 2/3 = 13/3)
your final answer would be 13/3
5 0
3 years ago
Use the graph to complete the statements.
anygoal [31]

The slope of JK is -6/5.

The slope of PQ is 12/ 15.

These lines are neither parallel nor perpendicular.

<u>Step-by-step explanation:</u>

From the graph shown,

It can be determined that the point J is (0,5) and K is (10,-7).

The point P is (-5,-8) and Q is (10,4).

The formula for slope is given by,

Slope = \frac{y2-y1}{x2-x1}

<u>To find the slope of line JK :</u>

J ⇒ (0,5) = (x1,y1)

K ⇒ (10,-7) = (x2,y2)

Slope of JK = \frac{-7-5}{10-0}

⇒ \frac{-12}{10}

⇒ \frac{-6}{5}

∴ The slope of JK is -6/5.

<u>To find the slope of line PQ :</u>

P ⇒ (-5,-8) = (x1,y1)

Q ⇒ (10,4) = (x2,y2)

Slope of PQ = \frac{4+8}{10+5}

⇒ \frac{12}{15}

∴ The slope of PQ is 12/ 15.

<u>To find the relation between two lines :</u>

  • The parallel lines have same slope.
  • The perpendicular lines have a slope of negative reciprocal.

∴ These lines are neither parallel nor perpendicular.

6 0
3 years ago
Read 2 more answers
Please help its due in 1 hour it would be best if you show work
aleksley [76]

Answer:

1:quadrant 1

2:quadrant 1

3:quadrant 2

4:quadrant 3

5:quadrant 1

6:quadrant 4

7:Z and quadrant 2

8: F and quadrant 1

9:A and quadrant 4

10: R and quadrant 4

11: N and quadrant 2

12: Q and quadrant 3

13a:the clock

13b:wonder wheel

13c:big coaster

13d: -1,2

Good luck

6 0
3 years ago
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