During an investigation of a cybercrime, the law enforcement officers came across a computer that had the hard drive encrypted.
1 answer:
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Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.
Answer:
A = 120
B = 40
C = 70
Solution:
As per the question:
Manufacturer forced to make 10 more type C clamps than the total of A and b:
10 + A + B = C (1)
Also, 3 times as many type B as type A clamps are:
A = 3B (2)
The total no. of clamps produced per day:
A + B + C = 330 (3)
The no. of each type manufactured per day:
Now, from eqn (1), and (3):
A + B + 10 + A + B = 330
2A + 2B = 320
A + B = 160 (4)
Now, from eqn (2) and (4):
3B + B = 160
B = 40
Since, A = 3B
A =
A = 120
Put the values of A and C in eqn (3):
120 + 40 + C = 330
C = 70
Answer:
Following are the code to this question:
file= open('book.txt') #open file
li= {} #define an empty list
for lines in file: # use for loop Split file data into words
d= lines.lower().strip(' !?').split() #define variable d that Add it to map
for val in d: #define loop to store data
if val not in li: #check value is not in list
li[val] = 0 #define list and assign value in 0
li[val] = li[val] + 1 #Sort the book data and add its value
m = sorted(li.items(),key = lambda x : -x[1]) #sorted value into the m variable
print(m[:10]) #print value
Output:
please find the attachment.
Explanation:
In the given python code first, we open the file "book.txt", in next line, an empty list is defined, that uses the for loop which can be described as follows:
- In the for loop is used, that reads the file data, and defines a variable "d", that stores the values into the map.
- In the next line another loop is used, that check file values, if values are the same type so, it adds values and writes it.
- In the last line, m variable is used, that sorts the values and use the slicing to print its value.
