2) Dorothy types 120 words per minute. How many words does Dorothy type in
2 answers:
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For the function 
We can use the formula for the axis of symetry, which is
With the values substituted, we get...
Therefore the axis of symmetry is
We can use the formula for the axis of symetry, which is
With the values substituted, we get...
Therefore the axis of symmetry is
Answer:
a) The horizontal asymptote is y = 0
The y-intercept is (0, 9)
b) The horizontal asymptote is y = 0
The y-intercept is (0, 5)
c) The horizontal asymptote is y = 3
The y-intercept is (0, 4)
d) The horizontal asymptote is y = 3
The y-intercept is (0, 4)
e) The horizontal asymptote is y = -1
The y-intercept is (0, 7)
The x-intercept is (-3, 0)
f) The asymptote is y = 2
The y-intercept is (0, 6)
Step-by-step explanation:
a) f(x) =
The asymptote is given as x → -∞, f(x) = → 0
∴ The horizontal asymptote is f(x) = y = 0
The y-intercept is given when x = 0, we get;
f(x) = = 9
The y-intercept is f(x) = (0, 9)
b) f(x) =
The asymptote is fx) = 0 as x → ∞
The asymptote is y = 0
Similar to question (1) above, the y-intercept is f(x) = = 5
The y-intercept is (0, 5)
c) f(x) = 3ˣ + 3
The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞
The asymptote is y = 3
The y-intercept is f(x) = 3⁰ + 3= 4
The y-intercept is (0, 4)
d) f(x) = 6⁻ˣ + 3
The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞
The horizontal asymptote is y = 3
The y-intercept is f(x) = 6⁻⁰ + 3 = 4
The y-intercept is (0, 4)
e) f(x) = - 1
The asymptote is → 0 and f(x) → -1 as x → -∞
The horizontal asymptote is y = -1
The y-intercept is f(x) = - 1 = 7
The y-intercept is (0, 7)
When f(x) = 0, - 1 = 0
= 1
x + 3 = 0, x = -3
The x-intercept is (-3, 0)
f)
The asymptote is → 0 and f(x) → 2 as x → ∞
The asymptote is y = 2
The y-intercept is f(x) =
The y-intercept is (0, 6)