Answer:
the answer is c 8.91g/cm³
Do you have a screen shot or picture of the problem?
For the first question, the correct answer among the choices listed is option A, a chocolate bar melting in hot car. It is an endothermic process because it absorbs heat energy for it to be melted. For the second question, it think the correct answer is the last option, <span>(-2222) + (-1182) - (-1144).</span>
Answer:
22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C
Explanation:
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:
P * V = n * R * T
where R is the molar constant of the gases and n the number of moles.
In this case you know:
- R= 0.082
![\frac{atm*L}{mol*K}](https://tex.z-dn.net/?f=%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D)
- T= 24 °C= 297 °K (being 0°C=273°K)
Replacing:
![7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K](https://tex.z-dn.net/?f=7.5%20atm%2A%202.3%20L%3Dn%2A0.082%20%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%20%2A297K)
Solving:
![n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B7.5%20atm%2A%202.3%20L%7D%7B0.082%20%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%20%2A297K%7D)
n=0.708 moles
Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?
![mass=\frac{0.708 moles*32 grams}{1mole}](https://tex.z-dn.net/?f=mass%3D%5Cfrac%7B0.708%20moles%2A32%20grams%7D%7B1mole%7D)
mass= 22.656 grams
<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>