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Tatiana [17]
2 years ago
9

What is the molar mass of pure nitrogen gas? (*diatomic element) ?????

Chemistry
1 answer:
Juli2301 [7.4K]2 years ago
3 0

Answer:

14.0067 g/mol

Explanation:

The molar mass of pure nitrogen is 14.0067 because when you look at the top right of an element on the periodic table of elements you can see the molar mass of an element. This can go for any other elements on the table, just look at the top right of the box. The molar mass of an element is also called the atomic weight. Hope this helps! :)

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Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. (1.8 x 1
slamgirl [31]

Answer : The answer is, 0.2\times 10^{-4}

Explanation :

Scientific notation : It is defined as the way or representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.

For example : 8000 is written as, 8.0\times 10^3  in this notation, the significant figure is, 1 but 0.8\times 10^4  in this notation, the significant figures are, 2

The given problem are :

\frac{1.8\times 10^{-2}}{9\times 10^2}=0.2\times 10^{-4}

According to the divide and multiplication rules of scientific figures, the final answer is only as precise as the value with the least number of significant figures.

Hence, the answer is, 0.2\times 10^{-4}

6 0
3 years ago
Read 2 more answers
MM H2O2 = 34.02 g/mol MM H2O = 18.02 g/mol MM O2 = 32 g/mol
Kaylis [27]

  The grams   of oxygen that  are   produced  is  228.8 grams


  <em>calculation</em>

2H₂O₂ → 2H₂O +O₂

Step 1:  use  the  mole ratio to determine the moles of O₂

from equation above H₂O₂:O₂  is   2:1

therefore the  moles of O₂  = 14.3 moles ×1/2 = 7.15   moles

Step 2:  find  mass   of O₂

mass = moles ×  molar mass

= 7.15 moles × 32 g/mol =228.8 g

3 0
3 years ago
Round to 4 significant figures: 42,561
arsen [322]

6 is the fourth significant figures

if the number behind it is 5 or more then 5, you must add 1 to the number and ALL the number behind it will turn into 0

so that the answer is 42560

7 0
3 years ago
How many valence electrons do the alkaline earth metals have?
fenix001 [56]

Answer:

\boxed{2}

Explanation:

Alkaline earth metals are in group 2. The number of valence electrons of elements in group 2 is 2.

5 0
3 years ago
Read 2 more answers
For the reaction: CH3NH2(aq) + H2O(aq) ⇌ CH3NH3 +(aq) + OH- Determine the change in the pH (ΔpH) for the addition of 6.7 M CH3NH
Korolek [52]

Answer:

The change in the pH (ΔpH) is 2,17

Explanation:

The reaction:

CH₃NH₂(aq) + H₂O(aq) ⇌ CH₃NH₃⁺(aq) + OH⁻

kb = \frac{[OH^{-}][CH_{3}NH_{3}^+]}{[CH_{3}NH_{2}]} <em>(1)</em>

In equilibrium, a solution of CH₃NH₂ 4,7M produces:

[CH₃NH₂] = 4,7 - x

[CH₃NH₃⁺] = x

[OH⁻] = x

Replacing in (1):

4,38x10^{-4} = \frac{x^2}{4,7-x}

x² + 4,38x10⁻⁴x - 2,0586x10⁻³ = 0

The solutions are:

x = -0,0456 No physical sense. There are not negative concentrations.

x = 0,04515 Real answer.

The concentration of [OH⁻] is 0,04515 M.

As pOH = -log [OH⁻] And pH+pOH = 14. The pH of this solution is:

<em>pH = 12,65</em>

The addition of 6,7M produce this changes in concentrations:

[CH₃NH₂] = 4,656 + x

[CH₃NH₃⁺] = 6,74515 - x

[OH⁻] = 0,04515 - x

Replacing in (1) you will obtain:

x² - 6,7907x + 0,3025 = 0

Solving for x:

x = 6,74586 No physical sense

x = 0,04484 Real answer.

Thus, [OH⁻] = 0,04515 - 0,044842 = 3,08x10⁻⁴M

pOH = 3,51.

<em>pH = 10,49</em>

Thus ΔpH is 12,65 - 10,49 = <em>2,16 ≈ 2,17</em>

I hope it helps!

4 0
3 years ago
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