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Olin [163]
3 years ago
7

How many valence electrons do the alkaline earth metals have?

Chemistry
2 answers:
fenix001 [56]3 years ago
5 0

Answer:

\boxed{2}

Explanation:

Alkaline earth metals are in group 2. The number of valence electrons of elements in group 2 is 2.

Vitek1552 [10]3 years ago
3 0

Hi there!

Answer:

Option B. 2.

-----------------

Alkaline earth metals consist of elements in group 2A of the periodic table, which contain 2 valence electrons.

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I have to do this for homework please help :)
kramer

Answer:

1..... nucleus

2......electron cloud

3.......protons

4........Neutrons

5..........electron

6............electrons

7...............Isotopes

8.....,...........ions

9....................charge

6 0
3 years ago
the reversible reaction N2(g) 3H2(g) <--> 2NH3(g) produces ammonia, which is a fertilizer. At equilibrium, a 1L flask cont
Alik [6]

Answer:

Explanation:

the chemical equilibrium constant can be easily calculated since the concentrations at equilibrium are given.the calculation shows the value of Kc for the reversible reaction and forward reaction

Download pdf
7 0
3 years ago
Using the Bohr model, determine the energy in joules of the photon produced when an electron in a Li2+ ion moves from the orbit
djverab [1.8K]

Answer:

1.64x10⁻¹⁸ J

Explanation:

By the Bohr model, the electrons surround the nucleus of the atom in shells or levels of energy. Each one has it's energy, and the electron doesn't fall to the nucleus because it can reach another level of energy, and then return to its level.

When the electrons go to another level, it absorbs energy, and then, when return, this energy is released, as a photon (generally as luminous energy). The value of the energy can be calculated by:

E = hc/λ

Where h is the Planck constant (6.626x10⁻³⁴ J.s), c is the light speed (3.00x10⁸ m/s), and λ is the wavelength of the photon.

The wavelength can be calculated by:

1/λ = R*(1/nf² - 1/ni²)

Where R is the Rydberg constant (1.097x10⁷ m⁻¹), nf is the final orbit, and ni the initial orbit. So:

1/λ = 1.097x10⁷ *(1/1² - 1/2²)

1/λ = 8.227x10⁶

λ = 1.215x10⁻⁷ m

So, the energy is:

E = (6.626x10⁻³⁴ * 3.00x10⁸)/(1.215x10⁻⁷)

E = 1.64x10⁻¹⁸ J

3 0
3 years ago
PLEASEEEE HELP MEE!
Ugo [173]

Answer:

2nd option

Explanation:

7 0
3 years ago
The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma
Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C=p_o= 187.54 mmHg

Vapor pressure of the solution at 65 °C= p_s

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water=n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol

Moles of ethylene glycol=n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}

p_s=173.83 mmHg

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0
3 years ago
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