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3 years ago

Chemical energy is stored in the bonds of (1 point)

Chemistry

1 answer:

Alex_Xolod [135]3 years ago

3 0

Answer:

Glucose molecules

Hope this will help u

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when a person strikes a match, potential energy in the match is transformed into which types of energy?

natulia [17]

Answer:

the answer is thermal and radiant

4 0

3 years ago

Read 2 more answers

Jack researched J.J. Thomson’s experiments. Read Jack’s summary below and find the error.

WINSTONCH [101]

Answer:

D. Error is in sentence 1. The beam was a cathode ray.

Explanation:

Legit just looked up his experiments and it said right off the bat he studied cathode rays not gamma.

8 0

3 years ago

An aluminum can holds 350 mL of gas at 0 C and 1.0 atm. what is the new volume if the can is heated to 10 C and the pressure ins

Mademuasel [1]

Answer:

Final volume of the gas is 4.837mL

Explanation:

Initial volume (V1) = 350mL = 0.35L

Initial temperature (T1) = 0°C = (0 + 273.15)k = 273.15k

Initial pressure (P1) = 1.0atm

Final volume (V2) = ?

Final temperature (T2) = 10°C = (10 + 273.15)k = 283.15K

Final pressure (P2) = 75atm

To solve this question, we'll have to use combined gas equation which is the combination of all gas law I.e Charle's laws, Boyle's law, Pressure law etc.

According to combined gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

Make V2 the subject of formula,

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (1.0 × 0.35 × 283.15) / (75 × 273.15)

V2 = 99.1025 / 20,486.25

V2 = 0.004837L

V2 = 4.837mL

The final volume of the gas is 4.837mL

5 0

3 years ago

Read 2 more answers

How long will a current of 0.995 A need to be passed through water (containing H2SO4) for 5.00 L of O2 to be produced at STP

DIA [1.3K]

Answer:

24 hours

Explanation:

The computation is shown below:

The needed mole of $O_2$ is

= 5 ÷22.4 = n

Also 1 mole of $O_2$ required four electric charge

Now the charge needed is

= n × 4 × 96,500 C

= 4 × 96,500 × 5 c ÷ 22.4

= 86160.714 C

Now

q = i t

t = q ÷ i

= 86160.714 C ÷ 0.995

= 86593.7 seconds

= 24 hours

Hence, the correct option is A.

3 0

3 years ago

In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo

NNADVOKAT [17]

Answer:

- 178 ºC

Explanation:

The ideal gas law states that :

PV = nRT,

where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.

For the initial conditions :

P₁ V₁ = n₁ R T₁ (1)

and for the final conditions:

P₂V₂= n₂ R T₂ where n₂ = n₁/2 then P₂ V₂ = n₁/2 T₂ (2)

Assuming V₂ = V₁ and dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂ / ( n₁ R T₁) then P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

T₂ = 95 - 273 = - 178 º C

6 0

3 years ago