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2 years ago

Chemical energy is stored in the bonds of (1 point)

Chemistry

1 answer:

Alex_Xolod [135]2 years ago

3 0

Answer:

Glucose molecules

Hope this will help u

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Calculate the pH of a solution in which one normal adult dose of aspirin (640 mg ) is dissolved in 10 ounces of water. Express y

d1i1m1o1n [39]

The pH of the solution in which one normal adult dose aspirin is dissolved is : 2.7

Given data :

mass of aspirin = 640 mg = 0.640 g

volume of water = 10 ounces = 0.295735 L

molar mass of aspirin = 180.16 g/mol

moles of aspirin = mass / molar mass = 0.00355 mol

<h3>Determine the pH of the solution </h3>

First step : calculate the concentration of aspirin

= moles of Aspirin / volume of water

= 0.00355 / 0.295735

= 0.012 M

Given that pKa of Aspirin = 3.5

pKa = -logKa

therefore ; Ka = $10^{-3.5}$ = $3.162 * 10^{-4}$

From the Ice table

$3.162 * 10^{-4}$ = $\frac{x + H^+}{[aspirin]}$ = $\frac{x^{2} }{0.012-x}$

given that the value of Ka is small we will ignore -x

x² = $3.162 * 10^{-4} * 0.012$

x = $1.948 * 10^{-3}$

Therefore

[ H⁺ ] = $1.948 * 10^{-3}$

given that

pH = - Log [ H⁺ ]

= - ( -3 + log 1.948 )

= 2.71 ≈ 2.7

Hence we can conclude that The pH of the solution in which one normal adult dose aspirin is dissolved is : 2.7

Learn more about Aspirin : brainly.com/question/2070753

4 0

1 year ago

A girl on a sled coasts down a hill. Her speed is 6.5 m/s when she reaches level ground at the bottom. The coefficient of kineti

pentagon [3]

Answer:

0000.45 turn this into a fraction and that your answer

Explanation:

did that help

4 0

3 years ago

PLEASE hurry

gizmo_the_mogwai [7]

Answer:

The answer is A.

Explanation:

8 0

3 years ago

Read 2 more answers

Give the relation of energy (E) and frequency (v) as given by Planck. Calculate the frequency and energy of a photon of radiatio

andrew-mc [135]

Solution:-1

$\\ \sf\longmapsto E=hv$

E denotes to Energy
h denotes to planks constant
v denotes to frequency.

Solution:-2

Wavelength=3000Å

$\boxed{\sf \lambda=\dfrac{c}{v}}$

$\\ \sf\longmapsto v=\dfrac{c}{\lambda}$

$\\ \sf\longmapsto v=\dfrac{3\times 10^8m/s}{3000\times 10^{-10}m}$

$\\ \sf\longmapsto v=0.001\times 10^{18}s^{-1}$

$\\ \sf\longmapsto v=1.0\times 10^{15}s^{-1}$

Now

$\\ \sf\longmapsto E=hv$

$\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 1.0\times 10^{15}s^{-1}$

$\\ \sf\longmapsto E=6.6\times 10^{-19}J$

4 0

2 years ago

4. How can different types of bonding affect the properties of substances?

lys-0071 [83]

Answer: Different types of chemical bonds and their varying intensity are directly responsible for some of the physical properties of minerals such as hardness, melting and boiling points, solubility, and conductivity. Chemical bonds also influence such other properties as crystal symmetry and cleavage. Hope this helps :)

Explanation:

5 0

3 years ago