Super heated liquid molten lava
Answer:
The answers are in order all you have to to do is put the letter in
Explanation:
Ur welcome
Answer:
When the pKa is 6.0, we can determine the fraction of protonated H is by:
pH = pKa + log [A]/[HA]
Where
A = Deprotonated imidazole side
HA = Protonated side
Given, pH = 5.0
5 = 6 + log [A]/[HA]
log [A]/[HA] = -1 (take antilog of both side)
[A]/[HA] = 0.1
The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 0.1
Given, pH = 7.5
7.5 = 6 + log [A]/[HA]
log [A]/[HA] = 1.5 (take antilog of both sides)
[A]/[HA] = 31.62
The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 31.62
Answer:
(based of what I would think )
Explanation:
If we didn't have decomposers, the waste left from the food we eat and what the wolves and stuff eat would grow into a problem, we would have ( i think) a mess or something
( more people can answer this better then me)
Answer:
In creature cells, if an answer that the cell is in has an equivalent measure of solute as within the cell does, the cell will continue as before size. On the off chance that there is more solute outside of the creature cell, the cell will recoil in light of the fact that the water will tail it out of the cell hypertonic arrangement. On the off chance that there is less solute outside of the creature cell, the cell will develop in light of the fact that the water will take after the more prominent solute within the cell hypotonic arrangement.
Explanation:
