All categories

3 years ago

Please I need your help

Physics

2 answers:

WINSTONCH [101]3 years ago

7 0

46 mph
4 m/s
10 m/s
vhyfbjgcvjgdcnjxtnnhdfbj

Alekssandra [29.7K]3 years ago

4 0

17. 36mph 40 takeaway 6

You might be interested in

Look at the diagram showing resistance and flow of electrons.

poizon [28]

The answer would be:

X: Low potential energy

Y: High Potential energy

Z: Flow of electrons

Z is clearly the flow of electrons, as shown by the arrow demonstrating the direction of the flow. So you can easily cross out choices B and C. Now, you can see that Y has more energy stored and X has a lot less, so you can conclude that Y has high potential energy while X has low potential energy.

8 0

3 years ago

Read 2 more answers

A grinding wheel 0.35 m in diameter rotates at 2600 rpm .

ddd [48]

It is calculated that a)The angular velocity of the wheel is 272.13 rad/s,

b)On the edge of the grinding wheel, the linear speed is 47.62 m/s,

and c) On the edge of the grinding wheel, the acceleration is 12958.08 m/s².

Calculation of angular velocity, linear speed & acceleration:

Provided that,

the diameter of the wheel = 0.35 m

So, the radius, r = 0.35/2 = 0.175 m

As 1 revolution = 2π rad

(a)the angular velocity, ω = 2600 rpm = $\frac{2600 * 2\pi }{60}$ rad/s

⇒ω = 272.13 rad/s

So, the angular velocity is 272.13 rad/s.

(b)The linear speed, v = r * ω

⇒v = 0.175 * 272.13

⇒v= 47.62 m/s

(c)The angular acceleration, $a=\frac{v^{2} }{r}$

$a = \frac{(47.62)^{2} }{0.175}$

⇒ $a$ = 12958.08 m/s²

Learn more about angular velocity here:

brainly.com/question/13649539

#SPJ1

6 0

2 years ago

A 2130 kg car is parked on a hill that makes a 15º angle with the horizontal. What is the normal force on the car?

valentinak56 [21]

Answer:

20573.67N

Explanation:

Given;

mass (m) of the car = 2130kg

angle of inclination Θ = 15⁰

The normal force (F) on the car is given by

F = mgcosΘ

where g is the acceleration due to gravity.

Taking g as 10 $m/s^{2}$ and substituting the values of m and Θ into the equation. We have;

F = 2130 x 10 x cos 15⁰

F = 2130 x 10 x 0.9659

F = 20573.67N

Therefore the normal force on the car is 20573.67N

7 0

4 years ago

The emission spectra you obtained from a star show a hydrogen spectrum that is shifted toward the blue end of the electromagneti

kvasek [131]

Answer:

The correct option is;

The star is moving toward Earth.

Explanation:

The shifting of the wavelength of light wave toward the blue end of the electromagnetic spectrum is termed blue shift.

A blue-shift of an electromagnetic wave corresponds to the wavelength decrease of the wave, which is equivalent increase in energy, resulting in an increase in the observed frequency of the wave.

Astronomers make use of the shifting of the wavelength of a wave to understand the relative motion of galaxies.

The wavelength of an approaching electromagnetic ave shifts towards the blue end of the electromagnetic spectrum because the wavelength is shorter.

The opposite of phenomenon is red-shift.

4 0

3 years ago

A bicycle rider traveling east at 10 km/hr sees a blue car pass her appearing to travel west at 50 km/hr. What is the blue car's

BigorU [14]

Answer:

$v_{bR} = 25 km/h$ towards west